Work and Energy of weightlifter

AI Thread Summary
A weightlifter lifts a 44 kg barbell 0.54 m for 24 repetitions, expending a total of 22,000 Joules of energy, factoring in 25% efficiency. The initial calculation of 230 Joules per repetition was correct, but the method to find total energy needed adjustment. To determine how many 480 Calorie donuts she can consume to match this energy expenditure, the conversion from Joules to calories involves dividing by 4.184. After converting, the final calculation will yield the number of donuts. The discussion emphasizes the importance of correctly applying efficiency in energy calculations.
paulsberardi
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Homework Statement


A weightlifter works out at the gym each day. Part of her routine is to lie on her back and lift a 44 kg barbell straight up from chest height to full arm extension, a distance of 0.54 m.

Homework Equations


If the weightlifter does 24 repetitions a day, what total energy does she expend on lifting? Assume 25 % efficiency.

The Attempt at a Solution


I looked at it, and could only see that the only change in energy is work. Work is 230J per repetition. I tried multiplying 230J by 24 in order to get the answer, but it was not correct.
 
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What about the efficiency? Only 25% efficiency means that 3/4 of the work done is wasted, and only 1/4 of it goes to actually lifting the weight.
 
Ya, I took the 230 J and multiplied it by 24, then by .25 but it won't accept the answer
 
paulsberardi said:
Ya, I took the 230 J and multiplied it by 24, then by .25 but it won't accept the answer

That's because multiplying it by 0.25 is not the right thing to do. You should read my post again, more carefully.
 
Ok I got the answer, its 22,000 Joules.
Part 3 of the question: How many 480 Calorie donuts can she eat a day to supply that energy?
I thought I could just convert the joules to calories by dividing by 4.184, then divide again by 480 to get number of donuts.
 
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