Work and Power of Skier

  • Thread starter scurry18
  • Start date
  • #1
12
1

Homework Statement


A skier of mass 70.0 kg is pulled up a slope by a motor-driven cable.
How much work is required to pull the skiera distance of 60.0m up a 30 degree slope (assumed frictionless) at a constant speed of 2.00 m/s?


Homework Equations


W=F (delta)r cos(theta)


The Attempt at a Solution


(delta)r= 60.0m
(theta)=30.0 degrees
Force=60sin30=30 J


Is this the correct start?

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
Hootenanny
Staff Emeritus
Science Advisor
Gold Member
9,621
7

Homework Statement


A skier of mass 70.0 kg is pulled up a slope by a motor-driven cable.
How much work is required to pull the skiera distance of 60.0m up a 30 degree slope (assumed frictionless) at a constant speed of 2.00 m/s?


Homework Equations


W=F (delta)r cos(theta)


The Attempt at a Solution


(delta)r= 60.0m
(theta)=30.0 degrees
It's all good up until this point:
Force=60sin30=30 J
Firstly force is measured in Newton's and not Joule's. Secondly, how did you calculate the force acting on the skier?

HINT: This problem is much more straight forward if one simply considered the gravitational potential energy of the skier.
 

Related Threads on Work and Power of Skier

  • Last Post
Replies
8
Views
5K
  • Last Post
Replies
1
Views
6K
  • Last Post
Replies
12
Views
3K
  • Last Post
Replies
2
Views
3K
  • Last Post
Replies
10
Views
5K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
1
Views
5K
  • Last Post
Replies
23
Views
8K
Replies
4
Views
1K
Top