Work done by cord on the pulley

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 3K views
annamal
Messages
393
Reaction score
33
Homework Statement
A 2-kg block on a frictionless inclined plane with an angle 40 degrees from the hoizontal. It has a cord attached to a pulley of mass 1 kg
and radius 20 cm. The acceleration of the block down the plane is 5 m/##s^2## (b) What is the work done by the cord on the pulley?
Relevant Equations
W = F*d
##W = \Delta(0.5*I*w^2)##
Screen Shot 2022-04-01 at 5.02.42 PM.png

torque = rF = I*aT/r
F = 0.5*aT*m_p
W = F (tension in rope)*d = 0.5*aT*m_p*d

Don't know because of unknown d
 
on Phys.org
annamal said:
Homework Statement:: A 2-kg block on a frictionless inclined plane with an angle 40 degrees from the hoizontal. It has a cord attached to a pulley of mass 1 kg
and radius 20 cm. The acceleration of the block down the plane is 5 m/##s^2## (b) What is the work done by the cord on the pulley?
Relevant Equations:: W = F*d
##W = \Delta(0.5*I*w^2)##

View attachment 299267
torque = rF = I*aT/r
F = 0.5*aT*m_p
W = F (tension in rope)*d = 0.5*aT*m_p*d

Don't know because of unknown d
Looks like you are asking about part (b) without having shown us part (a). Maybe d is given in part (a).
 
kuruman said:
Looks like you are asking about part (b) without having shown us part (a). Maybe d is given in part (a).
I figured out part a.
Part a just says "What is the acceleration of the block down the plane?" which I gave as 5 m/##s^2##
 
vela said:
It's a mistake in the book. The distance the block slides down the incline is 50 cm.
I see that. I am submitting an errata to openstax.
 
Reply
  • Like
Likes   Reactions: Lnewqban