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## Homework Statement

One mole of a dilute gas initially has a pressure equal to 1.00 atm, and a volume equal to 12.0 L. As the gas is slowly heated, the plot of its state on a PV diagram moves in a straight line to the final state. The gas now has a pressure equal to 5.00 atm, and a volume equal to 76.0 L.

(a) Find the work done by the gas.

19.2 kJ [correct]

(b) Find the heat absorbed by the gas.

I'm just not sure if I would add Internal Energy and the Work, or subtract the work

## Homework Equations

Δ U = Q + W

## The Attempt at a Solution

E = (3/2) nR(T2-T1)

T1= (P1V1)/nR

T2=(P2V2)/nR

T1=((1x10^5)(.012))/R

T2=((5x10^5)(.076))/R

Here is where I'm not so sure:

is it Q= E-W

-> Q= 36 kJ

or Q= E+W

-> Q=74.4 kJ