Thread moved from the technical forums, so no Homework Template is shown
The question is:
One kilogram of a gas with a molecular weight of 35 is contained in a balloon. The initial conditions are 27 C and 0.025 m^3. The gas is slowly heated isothermally until the final volume is 0.05m^3. The atmospheric conditions are 100 kPa and 27 C. The p-v-T relationship for the gas is given by pv = RT(1+bv) where R = 8.135 kpa-m^3/(kg mol-K) and b = 0.012 kg/m^3. Calculate the work done during the process for (a) the gas and (b) the gas and balloon.
pv = RT(1+bv) (for the gas p-v-T relation). Other equations may be molecular weight = g/mol? Conversions to K, the work equation (W = ∫pdv).
The Attempt at a Solution
With the info given I can calculate the an initial pressure and final pressure of the balloon (I think?), so for work done, its just W = p2v2 - p1v1? and for the gas, do I just integrate P, where P = RT(1+bv)/v ? When trying this integration for work done, the equation is dependent on the volume, so I'm a bit confused on if this is the work done by the balloon or the gas. The result I got from this method using integration was W = 1692.358 kJ (so probably gas?). Any guidance/suggestions would be appreciated!