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PVnRT81
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Homework Statement
A child lifts a bucket full of water from the bottom of a 5 meter deep well by pulling on a rope. The 10.0 kg bucket accelerates at a rate of 0.250 m/s/s.
Determine:
a. the work done on the bucket by the child
b. the work done on the bucket by gravity
c. the total work2. The attempt at a solution
Calculating the applied force by the child:
Fnet=ma
Fapp - mg = ma
Fapp = ma + mg
Fapp = (10 kg)(0.25 m/s/s) + (10 kg)(9.81 m/s/s)
Fapp = 100.6 N
Wchild = F x d
= (100.6 N)(5 m) = 503 J
Wgravity = F x d
= (9.81 m/s/s x 10 kg)(5 m) = 490.5 J
Wtotal = Wchild + Wgravity
= 503 J - 490.5 J = 12.5 J
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