- #1
Jim4592
- 49
- 0
I don't really have any clue on this problem...
A sled with mass 8.00 kg moves in a straight line on a frictionless horizontal surface. At one point in its path, its speed is 4.00 m/s. after it has traveled 2.5m beyond this point its speed is 6.00 m/s. Use the work energy relation to find the force acting on the sled, assuming that this force is constant and that it acts in the direction of the sleds motion.
W = ∆K
The only thing i can think of (which isn't the work energy theorem) is Work = 1/2 MVf2-1/2MVi2
W= 1/2*(8kg)*(6m/s)2-1/2(8kg)*(4m/s)^2
W = 80 J
then use Work = FS Cos(Θ)
80J = F*(2.5m)*Cos(180)
-32N = F
Homework Statement
A sled with mass 8.00 kg moves in a straight line on a frictionless horizontal surface. At one point in its path, its speed is 4.00 m/s. after it has traveled 2.5m beyond this point its speed is 6.00 m/s. Use the work energy relation to find the force acting on the sled, assuming that this force is constant and that it acts in the direction of the sleds motion.
Homework Equations
W = ∆K
The Attempt at a Solution
The only thing i can think of (which isn't the work energy theorem) is Work = 1/2 MVf2-1/2MVi2
W= 1/2*(8kg)*(6m/s)2-1/2(8kg)*(4m/s)^2
W = 80 J
then use Work = FS Cos(Θ)
80J = F*(2.5m)*Cos(180)
-32N = F