Work/Kinetic energy, running a race with mass and speed

AI Thread Summary
In the race scenario, both runners initially have the same kinetic energy, but one runner is faster. When the slower runner increases their speed by 21%, they match the speed of the faster runner. The key to solving the problem lies in using the kinetic energy formula, KE = 1/2mv², while recognizing that the masses and speeds differ. To find the mass of the faster runner, it's essential to set up two equations based on the given information about kinetic energy and speed. Properly labeling variables for each runner will help clarify the calculations needed to determine her mass.
Willy_Kingston
Messages
1
Reaction score
0

Homework Statement


You run a race with your friend. At first you each have the same kinetic energy, but then you find that she is beating you. When you increase your speed by 21%, you are running at the same speed she is. If your mass is 81 kg, what is her mass?
Your mass: 81kg
Your speed is increased by 21%
Her speed:?

Homework Equations


KE=1/2mv2



The Attempt at a Solution


1/2mv2=1/2mv2
1/2(81)v2=1/2?v2
 
Physics news on Phys.org
Willy_Kingston said:
1/2mv2=1/2mv2
That's not a terribly useful equation. Try using different symbols for different variables, e.g. the two masses and the two speeds. If you find subscripting a pain, combine upper and lower case, like Ma, Mb.
 
Willy_Kingston said:
1/2mv2=1/2mv2
1/2(81)v2=1/2?v2


Apart from the fact that you should give different names, you are considering both kinetic energy and speed equal at the same time... but it is not what the problem asks you...

When kinetic energy is the same, speeds are different; speeds are equal after you increasing speed. You will need two equations for solving this
Hint: write in equations the two different informations I gave you... it will solve by itself then :smile:
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top