Work Problems: Calculate Force for 150kg Object on 20* Incline

  • Thread starter Thread starter TexasCow
  • Start date Start date
  • Tags Tags
    Work
AI Thread Summary
To calculate the force required to move a 150kg object up a 20-degree incline at constant speed, one must consider the effects of gravity and friction. Normal forces do not perform work since they act perpendicular to the motion, while gravity does negative work when moving the object uphill. The net force must equal zero for constant speed, meaning all forces, including friction and gravity, must balance out. The work done by gravity can be calculated using the formula Wgravity = mgh, but it must account for the incline's angle and the distance moved along the plane. The discussion emphasizes the importance of understanding these forces and their roles in determining the required force for movement.
TexasCow
Messages
40
Reaction score
0
I'm working on some work problems.

Let's say we're moving an item up a 20* incline. It's mass is 150kg. The friction coefficient is .20.


Can gravity and/or normal forces "do" work?

Also, how does one calculate the minimum amount of force required to move this object at a constant speed?
 
Last edited:
Physics news on Phys.org
Normal forces act in a direction perpendicular to the contact point on the plane. If you're talking about moving an object along a plane, the normal force can do no work since it's perpendicular to the object's direction of motion.

In this situation, however, gravity CAN do work. If you are moving the object up, against the force of gravity, gravity is doing negative work on the object.

Constant speed means no acceleration. By Newton's second law, if a = 0 then F = 0 also. Thus, to find the conditions for constant speed, you find the situation in which the total net force on the object is 0 (all forces cancel one another).
 
Well for gravity, I did:

Wgravity=mgh=(150kg)(9.8)(sin30)

Is that correct?
 
Only if you move it along the plane a distance of 1 meter. You know from trig that your height would be d*sinθ where d is the distance along the plane and θ is the angle of inclination of the plane. Other than that, it's right!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .

Similar threads

Replies
13
Views
1K
Replies
5
Views
2K
Replies
4
Views
3K
Replies
2
Views
1K
Replies
7
Views
5K
Replies
11
Views
2K
Back
Top