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physics369
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Homework Statement
In an atom, an electron goes from the 4th energy level (at -0.26J x 10-18) to the 3rd energy level (at -0.59J x 10-18) and a photon is subsequently released.
How do you work out the frequency of the photo and its wavelength.
Homework Equations
E=hf
wavelength = c/f
The Attempt at a Solution
E=hf
Therefore, f=E/h so...
-0.59 - -0.26 = -0.33
so...
f = 0.33 x 10-18 / 6.63 x 10 -34
= 4.977 x10-14 Hz
And as wavelength = c/f...
wavelength = 3x108 (Speed of light) / 4.997 x10-14 = 6.0277 x1021
However, the wavelength surely can't be that large?! Where did I make a mistake?