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I have been given that this planet has a diameter of 1600km with a uniform density of 52000 per cubic metre. And if its moon is in a geostationary orbit around the planet and assuming that the sidereal is exactly 24 hours. How far is the geostationary orbit above the surface of the planet. And i need the answer in km.
I'm stuck in getting the mass of the planet as so far i have
radius of the geostationary orbit = cubed root of (GMpT2p over 4 pi 2)
so therefore the radius = cubed root of (6.6742 x 10-11 x (mass of the planet which i do not know how to find out x 864002 all over 4 pi 2)
some help would be much appreciated
thanks
I'm stuck in getting the mass of the planet as so far i have
radius of the geostationary orbit = cubed root of (GMpT2p over 4 pi 2)
so therefore the radius = cubed root of (6.6742 x 10-11 x (mass of the planet which i do not know how to find out x 864002 all over 4 pi 2)
some help would be much appreciated
thanks