Working with binomial identieies.

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chaotixmonjuish
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\binom{r}{k}=\frac{r}{r-k}\binom{n-1}{k}

I'm having problems proving this. However, here is my reasoning:

when factoring out an r you get

\frac{r*(r-1)!}{(r-k)!k!}
<br /> \frac{r}{r-k}*\frac{(r-1)!}{(r-k-1)!k!}<br />

Is this proper reasoning?
 
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That looks good. I think there is a typo in the problem the way it is stated. What is n?!

I think it should read (r-1)Ck on the right side, not (n-1)Ck.
 
Was that an actual proof of the identity?
 
It would be if you write r instead of n in the original statement as Russell Berty pointed out.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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