Write a partial sum for the power series,

ani9890
Messages
11
Reaction score
0
Write a partial sum for the power series, URGENT

Consider the function ln(1+4x).
Write a partial sum for the power series which represents this function consisting of the first 5 nonzero terms. For example, if the series were Sigma from n=0 to infinity of 3^nx^2n , you would write 1+3x2+3^2x^4+3^3x^6+3^4x^8. Also indicate the radius of convergence.

I got a power series = Sigma from n=0 to infinity of [(-1)^n(4^2n+1)(x^n+1)] / n+1
I got partial sum = 4x-32x^2+(1024/3)x^3-(16384/4)x^4+(262144/5)x^5
and radius of convergence = 1/4

radius of convergence is correct. But it says I have the partial sum wrong?
please help!
 
Physics news on Phys.org


ani9890 said:
Consider the function ln(1+4x).
I got a power series = Sigma from n=0 to infinity of [(-1)^n(4^2n+1)(x^n+1)] / n+1

This is wrong!

Consider the simpler function:
<br /> \ln(1 + y) = \sum_{n = 0}^{\infty}{\frac{(-1)^{n} y^{n + 1}}{n + 1}}<br />
Then, take y = 4 x. What does:
<br /> (4 \, x)^{n + 1} = ?<br />
equal to?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top