(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The first 3 parts of this 4 part problem were to derive the first 5 Hermite polynomials (thanks vela), The first 5 Legendre polynomials, and the first 5 Laguerre polynomials. Here is the last part:

Write the polynomial [tex]2x^4-x^3+3x^2+5x+2[/tex] in terms of each of the sets of orthogonal functions: Legendre polynomials, Hermite polynomials and Laguerre polynomials.

2. Relevant equations

Legendre polynomials

[tex]P_0 = 1[/tex]

[tex]P_1 = x[/tex]

[tex]P_2 = \frac{1}{2}(3x^2-1)[/tex]

[tex]P_3 = \frac{1}{2}(5x^3-3x)[/tex]

[tex]P_4 = \frac{1}{6}(35x^4-30x^2+3)[/tex]

Hermite polynomials

[tex]H_0=1[/tex]

[tex]H_1=2x[/tex]

[tex]H_2=4x^2-2[/tex]

[tex]H_3=8x^3-12x[/tex]

[tex]H_4=16x^4-48x^2+12[/tex]

Laguerre polynomials

[tex]L_0=1[/tex]

[tex]L_1=-x+1[/tex]

[tex]L_2=\frac{1}{2}(x^2-4x+2)[/tex]

[tex]L_3=\frac{1}{6}(-x^3+9x^2-18x+6)[/tex]

[tex]L_4=\frac{1}{24}(x^4-16x^3+72x^2-96x+24)[/tex]

3. The attempt at a solution

I first started with the Laguerre polynomials. I recognized that the 5th Laguerre polynomial was the only one that contained an x^4 term. I then knew that the only way to get an 2x^4 term in the polynomial I am trying to re-write would be to multiply L4 by 48. I then went on to look at the -x^3 term. I realized that since the multiple of L4 (48) couldn't be changed, I would have to multiply L3 by something that would give me the -x^3 term after it was added to the x^3 term in the L4 polynomial. I continued this path until I reached:

[tex]2x^4-x^3+3x^2+5x+2=48L_4-186L_3+276L_2-191L_1+55L_0[/tex]

I was not entirely sure what the question was asking so I took my first result to my professor. He said that the method used was correct (as long as my algebra was correct) but that it is not the method he had intended us to use. He said that I needed to use the equation:

[tex]f(x)=\sum_{n=1}a_n\phi_n(x)[/tex]

Where phi is either the Legendre, Hermite or Laguerre polynomials.

I went back through my notes and tutorial and found a way to express the coefficients a_n. However, the method used to find a_n was for periodic functions, namely the example shown was for the orthogonal set of sine and cosine.

I attempted to model a new solution based on the one for cosine and sine. I do not think that my new attempt is correct because while it yields the correct coefficients (at least for the L0 & L1) of the Laguerre polynomials, it seems a more complicated method then my first attempt. Also, I believe that trying to solve for the coefficients in the way I did is just a re-hashing of deriving the original polynomials.

What I did was I took the equation:

[tex]f(x)=\sum_{n=1}a_n\phi_n(x)[/tex]

and multiplied both sides by phi_m and then integrated both sides. Using orthogonality relationships I came up with:

[tex]a_n=\int_{0}^{\infty}f(x)\phi_n(x)dx[/tex]

For the Laguerre polynomials (normalized to 1)

Eventually this just boiled down to a similar linear algebra problem that I am supposed to avoid. Does anyone see another way?

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# Homework Help: Writing a polynomial in terms of other polynomials (Hermite, Legendre, Laguerre)

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