Writing the Lagrangians for different frames depending on how "the ball is dropped"

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Discussion Overview

The discussion revolves around the formulation of Lagrangians for a scenario involving a ball being dropped, focusing on the concepts of passive and active transformations in the context of homogeneity of space. Participants explore how to express Lagrangians for different frames of reference based on the position from which the ball is dropped.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant proposes that the Lagrangians ##L = \frac{1}{2}m\dot q^2 - mgy## and ##L' = \frac{1}{2} m\dot q'^2 - mg(y'+a)## represent a passive transformation, as they relate to the same physical situation viewed from different frames.
  • The same participant questions whether the transformation can also be considered active, suggesting that active transformation might involve dropping the ball from two different heights.
  • Another participant points out a potential redundancy in the discussion by referencing a previous thread on a similar topic.
  • Subsequent posts express a desire to close the previous thread due to perceived issues with the original question, indicating a lack of clarity or correctness in the earlier discussion.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether the transformations discussed are passive or active. The discussion remains unresolved regarding the correct classification of the transformations and the appropriate formulation of Lagrangians for the described scenarios.

Contextual Notes

There are limitations in the clarity of the questions posed, particularly regarding the definitions of passive and active transformations. The discussion does not resolve the mathematical or conceptual steps needed to fully articulate the Lagrangians for the different frames.

gionole
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I wanna be checking homogeneity of space(only interested in vertical) for simplicity and example we can do is "ball is dropped". To check homogeneity, we use either passive or active transformation and I'm interested in lagrangians.

I heard that we can write lagrangians such as: ##L = \frac{1}{2}m\dot q^2 - mgy## and ##L' = \frac{1}{2} m\dot q'^2 - mg(y'+a)##. This comes from the fact that ##y = y'+a##. (we seem to have y and y' frame).

Question 1: it seems to me that lagrangians that I wrote are an example of passive transformation, because of ##y = y'+a##. It's like the ball is only dropped from single location(one experiment), but we write lagrangians for the ball such as seen from each frame. Is this right ? as in, am I right that this is passive, or can we also call it active ?

Question 2: Active transformation seems such as ball must be dropped from 2 different locations(2 different locations). So we drop a ball from some height, and then we move up and drop it from higher location. How would we go about writing Lagrangians for each experiment ? using the same lagrangians as shown above doesn't seem correct to me, as I think it's passive.
 
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@berkeman would love to remove that thread as the question there is not asked correctly. but i can't delete it.
 
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gionole said:
@berkeman would love to remove that thread as the question there is not asked correctly. but i can't delete it.
Okay, I closed off the previous thread with a note pointing to this improved version here.
 
@berkeman can you close this as well ? Don't want people to spend time on it. I've figured it out. Thanks.
 
Sure, thanks for the heads-up. I've closed off this thread now; I'm glad that you figured it out.
 
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