- #1

roeb

- 107

- 1

## Homework Statement

In polar coords: y = rsin([tex]\theta[/tex])

y' = dy/dt = r'sin([tex]\theta[/tex]) + rcos([tex]\theta[/tex]) [tex]\theta[/tex]'

If I want [tex]\partial r' / \partial y' [/tex] can I just solve for r' and take the derivative of y'?

so

[tex]\partial r' / \partial y' = 1 / sin \theta[/tex]

I am hoping this is incorrect because I am getting the wrong answer on another part of a problem...