X and y components in force problem

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SUMMARY

The discussion focuses on resolving the forces acting on a 10 kg sled being pulled at an angle of 35 degrees east of north by a force of 100 N, alongside a 150 N force directed due east and a friction force of 50 N. Participants emphasize the need to calculate the x (east) and y (north) components of the 100 N tension force using trigonometric functions. Specifically, the east component is derived using the cosine function, while the north component is calculated using the sine function. The final goal is to determine the sled's acceleration, both in magnitude and direction.

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The problem is:
A 10 kg sled is pulled at an angle of 35 o east of north by a force of 100 N and with a force of 150 N directed due east. A friction force of 50 N acts as well. What is the acceleration (both magnitude and direction of the sled.

My question - could someone help me properly draw out the x and y components of the angled Force ? Thanks in advance
 
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The Tension Force (Ft) is in the direction of the rope and you are told that the total Ft=100 N

So you want to figure out the east and north components of this force. Draw a triangle with the hypotenuse as Ft=100 N

To get the east component, you want to take cos(180-35) because cos(x)=adjacent(east)/hypotenuse , now solve for the adjacent(east) component. You can do the same to get the north component, but by using sin(x)=opposite(north)/hypotenuse
 

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