X-Ray diffraction - The Von Laue's equation

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SUMMARY

The discussion focuses on X-Ray diffraction using Laue's treatment, specifically addressing the derivation of equations related to path difference and phase difference. Key equations mentioned include PA as r.n_{o} and ∅_{r}=\frac{2π}{λ}(r.N), which are fundamental in understanding the relationship between wave vectors and path differences. The participants clarify that phase difference is defined as \phir=wavevector×pathdifference, with the wavevector being 2π/λ. The conversation emphasizes the importance of these equations in the context of X-Ray diffraction analysis.

PREREQUISITES
  • Understanding of X-Ray diffraction principles
  • Familiarity with Laue's treatment in crystallography
  • Knowledge of wave mechanics, specifically wave vectors
  • Basic algebra and trigonometry for manipulating equations
NEXT STEPS
  • Study the derivation of Laue's equations in X-Ray diffraction
  • Learn about wave vector calculations in physics
  • Explore the relationship between path difference and phase difference in wave mechanics
  • Investigate applications of X-Ray diffraction in material science
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Students and professionals in physics, materials science, and engineering who are interested in X-Ray diffraction techniques and their mathematical foundations.

shayaan_musta
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Hello experts!

I have some questions related to the X-Ray Diffraction using Laue's treatment.

I have attached some images. I have marked in red what I want to ask.

Kindly tell me where did these equations come? Is there any low level physics included too, if so then kindly guide me through.

1.jpg


How do you write PA as r.n_{o}?
Where does it come, ∅_{r}=\frac{2π}{λ}(r.N). I know this is path difference. But where does the (r.N) come?

2.jpg


How path difference become equal to 2πh^{'}=2πnh
and,
How aNcosα=2asinθcosα ?
and similarly,
How 2asinθcosα=h^{'}λ=nhλ

Thank you all.
 
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Hi, with only high-school knowledge you can answer your questions. PA=OP.cos(PA,OP)=OP.PA/PA.cos(PA,OP)=OP.n0
\phir is phase difference, not path difference
\phir=wavevector×pathdifference
wavevector=2π/λ
 
shayaan_musta said:
2.jpg

How phase difference become equal to 2πh^{'}=2πnh
and,
How aNcosα=2asinθcosα ?
and similarly,
How 2asinθcosα=h^{'}λ=nhλ

Thank you all.

Thank you for answer. I am sorry, I lost my connection therefore I have late in reply. So can you answer this one too?
 

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