Y-intercept in Weight-Mass Graph

  • Thread starter Thread starter SeLe92720
  • Start date Start date
  • Tags Tags
    Graph
AI Thread Summary
The vertical intercept of a weight-mass graph represents the weight of an object when its mass is zero, which is zero weight. This indicates that weight is directly proportional to mass, as weight is the force exerted by gravity on an object. On Earth, an object cannot have weight without mass, reinforcing the concept that both are intrinsically linked. The discussion emphasizes that the y-intercept being zero aligns with the fundamental relationship between mass and weight. Understanding this relationship is crucial for interpreting weight-mass graphs accurately.
SeLe92720
Messages
1
Reaction score
0

Homework Statement


What is the physical meaning of the vertical intercept for weight-mass graph?


Homework Equations



there is no equations

The Attempt at a Solution


I know that the y-intercept is zero.
 
Physics news on Phys.org
Think about it.. What is the relationship between mass and weight? On Earth, can there be one without the other?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top