You throw several coins into a pool for a diving game

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The discussion revolves around physics problems related to optics and light behavior in different mediums. It addresses how the apparent depth of coins in water differs from their actual depth, with options suggesting they appear deeper or shallower. Additionally, it explores the reflection of light from a soap bubble and the impact of a diamond coating on flint glass regarding destructive interference. The conversation also includes calculations involving light passing through slits and determining fringe separation. Overall, the thread emphasizes understanding light behavior in various contexts and solving related physics problems.
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Homework Statement


you throw several coins into a pool for a diving game. how does their apparent depth (if you are looking from the edge of the pool into the water) compare to their actual depth?

a. it appears deeper
b. it appears shallower
c. there's no difference
d. depends on the index of refraction of the coin (i know this is not right)
e. Depends on where ur standing

A soap bubble (n=1.25) is floating in and filled with air. thickness of the bubble wall is 100nm, which of the following wavelengths of visible light is STRONGLY reflected?
a. 620nm (red) b. 580nm (yellow) c. 540nm (green) d. 500 nm(blue) OR NONE


1. extra dense flint glass has one of the highest indices of refraction of any type of glass. Suppose a beam of light passes from air into a block of extra dense flint glass.
A. if the light has an angle of incidence of 72 degrees and and angle of refraction of 34 degrees, what is the speed of light in the glass?

Suppose the light hiting the glass is of a single wavelength (Lambda air = 500nm), and the glass now has a THIN FILM of diamond (n=2.42) coating its surface.
B. What is the smallest, non-zero thickness of the diamond layer that will cause the flint glass to APPEAR DARK (destructive interference)?

2. Light with a wavelength of 644nm uniformly illuminates a double slit. a screen is located 2m from the slits. What is the separation between the slits if the THIRD ORDER dark fringe is located at 0.125 degrees ? What is the distance between the FOURTH AND SECOND ORDER LIGHT FRINGE?


Homework Equations


Xm = (m*lambda wavelength*L) / (distance between slits)

m*lambda wavelength = d(sintheta)


The Attempt at a Solution

 
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Hi nomalware80, have you tried these questions at all? Where do you get stuck, have you tried chucking some coins in a glass of water to answer questions 1.
 
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