Young's Modulus Brass Wire Question

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The discussion revolves around calculating the cross-sectional area of a brass wire subjected to a 10 kg load, which vibrates vertically at a frequency of 10 Hz. The Young's modulus for brass is given as 9x10^10. Participants express confusion about incorporating the frequency of vibration into the Young's modulus calculations, particularly how it relates to Hooke's law. The connection between the mass, frequency, and the spring constant is highlighted as crucial for solving the problem. Overall, the conversation focuses on integrating concepts of simple harmonic motion (SHM) with Young's modulus to determine the wire's properties.
gspsaku
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Homework Statement


A 10 kg load suspended by a brass wire 10 m long is observed to vibrate vertically in SHM at a frequency of 10 vib/s. Given that the Young's modulus for brass is
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, what is the cross-sectional area of the wire?

So we know:
m = 10kg
l = 10m
f = 10Hz
Y = 9x10^10

Homework Equations



Y = (F/A)/(delta l/l)

The Attempt at a Solution


We have solved Young's modulus problems but they have been very basic. Since this one includes what appears to be some sort of vertical movement/vibration, I don't know what to do because I don't know how the vib/s or Hz comes into play...
 
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If you have studied SHM, then you know that a body moves in SHM when the body is subject to a force obeying Hooke's law. Did you learn how the vibrational frequency is related to the mass of the body and the force constant in Hooke's law?
 
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TSny said:
If you have studied SHM, then you know that a body moves in SHM when the body is subject to a force obeying Hooke's law. Did you learn how the vibrational frequency is related to the mass of the body and the force constant in Hooke's law?
We did and I'm working on it and I think I'm on my way...

At first I was so confused by the SHM because I had never seen it with any Young's mod problem but I am using Hooke's and Young's mod to find the actual stretch.

I was able to isolate the k constant and I think maybe I can solve this
 
Sounds good.
 
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