Which members in the truss are zero force?

AI Thread Summary
In the discussion about identifying zero-force members in a truss, it is noted that Joint C, despite being unloaded and having two non-collinear members, does not have any zero-force members due to the presence of four connected members. The lack of a specific rule for four-member joints complicates the identification process. Additionally, Joints E and K are confirmed to be loaded due to reaction forces. Participants agree that equilibrium calculations may be necessary to analyze the situation further, but the presence of four members makes it challenging to identify zero-force members. The conversation emphasizes the complexity of analyzing joints with multiple connections in truss structures.
DiamondV
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Homework Statement


Okay, I need help quick, exam in few hours, I won't be able to reply to this later.

http://puu.sh/lQeXl/42907b0a12.jpg

In my lectures notes this is given. In the example shown with it, the one on the right in particular. Look at Joint C, it is unloaded, it also has to members connected to CG and CH both of which are non-collinear, but neither is zero force? I know technically there are 4 members connected to Joint C but I have no rule for 4 members so I just thought maybe we just ignore the other two(sounds weird) No other info about zero force members was given.

Also one more thing, Joints E and K, they are loaded due to the reaction forces correct?

Homework Equations


N/A

The Attempt at a Solution


N/A[/B]
 
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DiamondV said:
no rule for 4 members
That simply means you can not identify a zero-force member there.
DiamondV said:
Joints E and K, they are loaded due to the reaction forces correct?
Correct

Good luck with your test ! :smile:

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BvU said:
That simply means you can not identify a zero-force member there.
Correct

Good luck with your test ! :smile:

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So I would have to do out the equilibrium calculations to find if there are any zero force members connected to a joint with 4 members.
 
Don't think that will help: then you still have 4 members (and a force). But I'm not an expert, so not sure.
 
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Hi all, I have a structural engineering book from 1979. I am trying to follow it as best as I can. I have come to a formula that calculates the rotations in radians at the rigid joint that requires an iterative procedure. This equation comes in the form of: $$ x_i = \frac {Q_ih_i + Q_{i+1}h_{i+1}}{4K} + \frac {C}{K}x_{i-1} + \frac {C}{K}x_{i+1} $$ Where: ## Q ## is the horizontal storey shear ## h ## is the storey height ## K = (6G_i + C_i + C_{i+1}) ## ## G = \frac {I_g}{h} ## ## C...

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