Zero State, Stable Equilibrium, Dynamic System

essie52
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Could someone please help?

The question reads:

For which real numbers "k" is the zero state a stable equilibrium of the dynamic system (vector(x))(t+1)=A(vector(x))(t)?

A= [0.1 k ## 0.3 0.3] --> a 2 x 2 matrix with ## separating the two rows.

So, my thought is I need to find the eigenvalues. In order to do this I calculated the characteristic polynomial as:

x^2 - 0.4x + 0.03 - 0.3k = 0 with x representing eigenvalues

Using the quadratic formula I found that the (real) eigenvalues are (2 +/- (sqrt(1+30k)))/10 and for the zero state to be in stable equilibrium sqrt(1+30k) < 8. Hence, k < 21/10 (for stable equilibrium).

My question is how do I figure out the values for k if the eigenvalues are complex?

Do I solve the inequality 2 +/- (sqrt(-1-30k)) < 8?

Thanks!
 
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Got it! Thanks anyway!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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