- #1
Senjai
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[SOLVED] Q=mcT heat problem, were did i go wrong?
If a 45g sample of aluminum at 22 degrees C is given 6.0 x 10^3 J of heat, what will its final temperature be?
[tex]Q = mc \Delta T[/tex]
i found in my textbook that aluminum has a specific heat capacity of 900
so c = 900.
[tex]Q = mc \Delta T [/tex]
[tex]Q = mc( T' - T ) [/tex]
[tex]T' - T = \frac{Q}{mc} [/tex]
[tex]T' = \frac{Q + T}{mc}[/tex]
[tex]T' = \frac{(6.0 x 10^3 J) + 22\deg}{(0.045kg)(900)} [/tex]
Homework Statement
If a 45g sample of aluminum at 22 degrees C is given 6.0 x 10^3 J of heat, what will its final temperature be?
Homework Equations
[tex]Q = mc \Delta T[/tex]
The Attempt at a Solution
i found in my textbook that aluminum has a specific heat capacity of 900
so c = 900.
[tex]Q = mc \Delta T [/tex]
[tex]Q = mc( T' - T ) [/tex]
[tex]T' - T = \frac{Q}{mc} [/tex]
[tex]T' = \frac{Q + T}{mc}[/tex]
[tex]T' = \frac{(6.0 x 10^3 J) + 22\deg}{(0.045kg)(900)} [/tex]