Calculating the speed of a crane (using pythagoras) with different x & y speeds

by Calico5
Tags: pythagoras theorem
 P: 2 Hi, 1. The problem statement, all variables and given/known data I'm designing a C++ program to simulate the operation of a steel processing warehouse. Part of my code requires me to calculate the time it takes for a crane to move certain distances (mainly diagonal ones) across a large shelving rack. 2. Relevant equations The crane moves at different speeds in different directions. Maximum x speed = 40m/min Maximum y speed = 12.5m/min I was thinking of using pythagoras theorem somehow to solves this (although its not required to be done this way) so: c2 = a2 +b2 3. The attempt at a solution I was thinking of using: time = distance/speed to calculate the time for each movement in x direction and y direction. Then using pythagoras theorem on the times to get the diagonal movement time. So an example would be: X-Time = 6/40 = 0.15min Y-Time = 4/12.5 = 0.32min Z-Time = SQRT(0.152+0.322) = 0.353min Would that be correct? Im not sure if i can apply pythagoras theorem to time like that. Any Help is appreciated Thanks
P: 109
 Quote by Calico5 Hi, 1. The problem statement, all variables and given/known data I'm designing a C++ program to simulate the operation of a steel processing warehouse. Part of my code requires me to calculate the time it takes for a crane to move certain distances (mainly diagonal ones) across a large shelving rack. 2. Relevant equations The crane moves at different speeds in different directions. Maximum x speed = 40m/min Maximum y speed = 12.5m/min I was thinking of using pythagoras theorem somehow to solves this (although its not required to be done this way) so: c2 = a2 +b2 3. The attempt at a solution I was thinking of using: time = distance/speed to calculate the time for each movement in x direction and y direction. Then using pythagoras theorem on the times to get the diagonal movement time. So an example would be: X-Time = 6/40 = 0.15min Y-Time = 4/12.5 = 0.32min Z-Time = SQRT(0.152+0.322) = 0.353min Would that be correct? Im not sure if i can apply pythagoras theorem to time like that. Any Help is appreciated Thanks

I would use Pythagorean theorem on the velocity and distance. Then use t = d/v. You would find how far the crane moves along the diagonal, and if the x-y speeds are constant, how fast it is moving along the diagonal so you could calculate the time.
 P: 2 Thank you for the reply Apphysicist :) Ahh right, i see. Tried out your method and got the following: ZDistance = SQRT(42 + 62) = 7.211 ZSpeed = SQRT(402 + 12.52) = 41.907 t=d/v = 7.211/41.907 = 0.17min That seems a bit quick doesnt it? given that the previous results were: X-Time = 0.15min Y-Time = 0.32min i would have thought the pythagoras time would be closer to the slowest time. No?

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