Find Remaining NO Concentration: 2NO + 2H2 → N2 + 2H2O, 0.006M NO, 0.002M H2

[reyrey389]

2NO + 2H2 --> N2 + 2H2O

The concentration of NO is 0.006 M and the concentration for H2 is 0.002M. How can I find the concentration of NO remaining when one-half of the original amount of H2 has been consumed?

if you can also show me how it would be done if the reaction was not 1:1, that would help alot. thanks

 

[Borek]

Please read your private mail - click on the "Your notifications" link in the upper right corner of the page.

It is a basic stoichiometry. To simplify things you can assume 1L volume. How many moles of H₂ reacted if half was consumed? How many moles of NO reacted with this amount of hydrogen?

 

[xplosiv3s]

2NO + 2H2 --> N2 + 2H2O

The concentration of NO is 0.006 M and the concentration for H2 is 0.002M. How can I find the concentration of NO remaining when one-half of the original amount of H2 has been consumed?

if you can also show me how it would be done if the reaction was not 1:1, that would help alot. thanks

Here the molar ratio for NO and H2 is 1:1.

We know that 1/2 of original H2 remains
0.002/2 =0.001
for every 1 NO 1 H2 gets used up
for every 0.001 NO 0.001 H2 gets used up

0.006-0.001 =0.005 NO remaining

 

[Borek]

Have you read the forum rules? Please don't do homework for others. A week passed, but it is not a reason to give final answers.

 

[DeeNos]

To find the remaining concentration of NO, we can use the mole ratio between NO and H2 in the balanced chemical equation. In this case, the ratio is 2:2 or 1:1. This means that for every 2 moles of NO consumed, 2 moles of H2 are also consumed.

Since we know that 0.002 M of H2 has been consumed, this means that 0.002 M of NO has also been consumed. Therefore, the remaining concentration of NO is 0.006 M - 0.002 M = 0.004 M.

If the reaction was not 1:1, we would need to use the stoichiometric coefficients in the balanced chemical equation to determine the mole ratio between the two reactants. For example, if the reaction was 2NO + 3H2 → N2 + 2H2O, the mole ratio between NO and H2 would be 2:3. This means that for every 2 moles of NO consumed, 3 moles of H2 are consumed.

Using this ratio, we can calculate the remaining concentration of NO by first determining the moles of H2 consumed (0.002 M x 3 = 0.006 moles) and then using the mole ratio to calculate the moles of NO consumed (0.006 moles x 2/3 = 0.004 moles). Finally, we can convert the moles of NO consumed to concentration by dividing by the total volume of the solution.

Therefore, the remaining concentration of NO would be 0.004 moles / total volume of solution.