askor said:
davenn said:
Have you come across Kirchoff's Laws?askor said:
What's needed in a problem like this is a systematic approach.You have reduced the circuit already by converting those two resistors to just one. Then you use Kirchoff's laws to produce some simultaneous equations for the currents and voltages around a circuit. Looks a pain but this problem is not too hard. There is no point in my explaining Kirchoff if you know it already.askor said:
The current in an electric circuit can be determined by using Ohm's Law, which states that current (I) is equal to the voltage (V) divided by the resistance (R). This can be expressed as I = V/R.
In a series circuit, the components are connected in a single loop, so the same current flows through each component. In a parallel circuit, the components are connected in multiple branches, so the current is divided between them.
The resistance of a resistor can be calculated using the formula R = V/I, where R is the resistance in ohms, V is the voltage across the resistor, and I is the current flowing through the resistor.
To solve a circuit with multiple resistors, you can use a combination of series and parallel circuit analysis. First, analyze each branch of the circuit separately using the appropriate equations. Then, combine the results to determine the overall current, voltage, and resistance of the circuit.
Kirchhoff's Voltage Law (KVL) states that the sum of all voltage drops in a closed loop is equal to the sum of all voltage sources in the same loop. This law is used in circuit analysis to determine the unknown voltages in a circuit by setting up equations based on the voltage drops and sources in the loop.