Recent content by barthayn

I don't see how to start off a then because I get something over the initial velocity squared, which is zero. As a result, it should not be defined. Any hints?

Homework Statement A 5000kg interceptor rocket is launched at an angle of 44.7 degrees. The thrust of the rocket motor is 140,700N a) Find an equation y(x) that describes the rocket's trajectory b) What shape is the trajectory? c) At what elevation does the rocket reach the speed of sound...

Yeah, I changed my therefore statement to as follows: Therefore, by counterexample, even through that g'(x) is periodic g(x) is not periodic because it does not repeat its values in regular intervals or periods. As seen in the graph below: *Graph of g(x) being shown that it is always increasing*.

Yes, I see my mistake. P is nothing more that the horizontal phase shift of the periodic function. For it to remain the same it would have to be 2[b]k[/k]pi, where k is a natural number, thus always yielding cos(x).

Thank you for your help. To show this it is as follows: let g'(x) = f'(x+p) - f'(x) Assume that f'(x+p) = cosx and f'(x) = 1 Therefore, we can conclude that g'(x) is periodic because it is cosx-1 but g(x) = sinx-x.Sinx-x is not periodic because it has no period and/or oscillation in which...

Thank you very much. I think I understand. F'(x) is periodic because it is cos(x)+1, but f(x) is not periodic because it does not have a phase point in which is does not repeat itself. It increases at a certain period time, but never repeats itself, correct? This is assuming that p is 0 right?

This is where I am at. f(x+p) = f(x) Let g(x) = f(x+p)-f(x) g'(x) = f'(x+p)-f'(x). g'(x) = f'(x+p)-f'(x) because the constant p'=0. Therefore, it becomes g'(x) = f'(x+p)-f'(x). The only point that g'(x) = 0 is when p=0 and thereby, making f'(x+o)=f'(x) => that g'(x)=0. From here I can...

I don't understand how it could not be true. All the functions that were periodic had a derivative that was also periodic that we had taken up so far in class. I can only think that sin(x^-1) = e(x) that e'(x) would not be periodic simply because e(x) has not period but is periodic.

taking G'(x)= would only give f'(x+p)-f'(x) correct? How is this proof of the claim? Don't you have to prove it for all cases of the situation?

Homework Statement A function f(x) has periodic derivative. In other words, f'(x +p) = f'(x) for some real value of p. Is f(x) necessarily periodic? Prove or give a counterexample. I believe it is true simply because of trigonometric functions. However, I do not know how to prove it. I...

Update. I proved the question for a. It turns out that I forgot that a/a = 1 and not equal to 0 (lol) How do I do b. I don't understand how you can solve for the angle that it can be equal to to give you only one angle that you have to use so that the water can enter into the window when there...

Homework Statement A firefighter on the street is trying to spray water from a hose to a building a horizontal distance x1 through a window a height h above the height of the hose (see figure in image below). For a given initial speed vo of water from the hose, we would like to future out if...

Thanks, I forgot to half the area found because it was a triangle. To prove me correct I took the integral. I got 100 cm from x. So the final answer is 180.27cm from the origin, correct?

Homework Statement A rocket-powered hockey puck moves on a horizontal frictionless table. Figure EX4.8 at the top of the next column shows graphs of vx and vy, the x- and y-components of the puck's velocity. The puck starts at the origin. a. In which direction is the puck moving at t = 2s...

Yupperz! :smile: