I got a doubt...Master Slave Flip flops are introduced in order to avoid the racing condition...Since, slave can't be working when master's clock is high there would be no racing in original Master Slave's circuit...But, can the method described by you avoid racing of flip-flops...I got this...
1.How to set the initial state of the Pseudo Random Sequence Generator?
2. I'm using 74LS74 D-flipflop.I'm unclear how to use clear and preset enable inputs to set the initial sequence.
3. I tried doing the experiment by directly giving the 0001 sequence through respective...
Thank you very much...
that helped me a lot...
"Does my post come under home work question?"
Yeah, but I want to know every alternative...
Thank you...
Hi everybody...
This is not actually a home work question...i didn't find any other place to post it...
1.Can we make master slave jk flipflop using 74LS73 ic's which containt two individual jk flipflops?
2.JK flip flop has two 3-input NAND gates and the outputs are fed back from its...
Hi, I'm a newbie...
I came to know that there are many types of transistors available in the market with high, middle, and low β values.But, I don't have any idea about applications of each in detail.Can anybody tell me the applications of high β, middle β, and low β valued CE...
As 2A and 1A are reaching node 2...3A must leave it..
So, i1=3A, am I correct..?
and wow i2=3A...I got it now ...I think I'm correct...amn't I?
Thank you very very much...
Thanks for your reply...
I visited this link http://www.animations.physics.unsw.edu.au/jw/electricmotors.html"
and found a graph of DC voltage...though there is no negative cycle...graph touches the x-axis for every cycle which means that it does have zero value for every cycle...
I...
Thank you
Yes, there are four branches coming together at node 1.Currents are specified for two of the branches.
At node 1 KCL: -1+1+[(v1-(-5))/3]+[v1-(v2+10)]/2=0
Did I write it correctly?
Thanks...
1. Find the power delivered by the 5V Voltage source in the network of Fig.
This is my attept at solution:
At node 1 V1...assuming current leaving V1:
KCL equation: -1A+1A+[(V1-5)/3]+[(V1-(V2-10))/2]=0
At node 2 V2...assuming current leaving V2:
KCL equation: -2A-1A+[V2-(V1+10)]=0...
What is the difference between manual interruption by switching on and off,and the zero crossing point?.I think the wearing of the equipment occurs when we switch on and off.
Is there any sensitive device which cannot even bear the such a small time interruption of zero crossing point?
How can equipments work in ac current even it is oscillating from +ve to -ve and to zero?
Alternating current is alternation of positive and negative values.If we consider the sinusoidal case,the current value becomes zero,negative,positive in a cycle.In that case,how can electrical equipment...