Recent content by danielI

So I need help with this diff eq. A train is placed in the tunnel AB and is will roll through it under its own weight, stop and return. Show that the time for a complete round trip is the same for all tunnels and calculate it. Using the fact that the force of gravity (inside the earth) is...

The reason I thought so was because the 200kg mass accelerates and so would the 150kg mass. While the 200*9,81 force in system 2 doesn't do that. Ofcourse there is some logical error with my reasoning. Also, here are all the videos...

Doc Al, My first theory regarding the picture was that 1 will accelerate but not system 2 since the 150kg cylinder is being pulled with a constan force. But this is wrong. I know how to calculate system 1. T - 150*9,81 = 150a 200*9,81 - T = 200a + => a = 1.401m/s^2 => T = 1681,65N...

At the end of this lesson. http://mfile.akamai.com/7870/rm/mitstorage.download.akamai.com/7870/8/8.01/f99/videolectures/wl99lec6-300k.rm Why does the lower string break, and then the upper and finally the lower one again? Has it anything to do with the speed he is pulling with? Look at the...

How awfull isn't this? I've been working on this problem for hours now but my brain wasn't getting anywhere. While typing this message which was originally an explanation of my ideas I managed to come up with the solution. Basically at A we have the force mg while we at B have two forces mg and...

If the slider along the smoth guide (i.e., no friction) on the horisontal plane has the speed 1.4m/s at A, what force F will the guide exert on the slider at point B? The weight of the slide is 0.12kg http://img522.imageshack.us/img522/750/slider4lo.png I'm able to calculate F at A = mg =...

Hey! In a test of resistance to motion in an oil bath, a small steel ball of mass m is released from rest at the surface. If the resistance to motion is given by R = kv where k is a constant, derive an expression for the depth h required for the ball to reach a velocity v. mg - kv = ma =...

Hello durt Okay, since the tilting part was wrong we keep the R_x and remove the R_y. Let the blue dot be origo. We will have two torques, the one by gravity and the one created by the force P. We start of with the one created by gravity. M_1 = mgd This will be counterclockwise. Then...

God day! The magnitude of force P is slowly increased. Does the homogeneous box of mass m slip or tip first? State the value of P which would cause each occurrence. Neglect any effect of the size of the small feet. http://img75.imageshack.us/img75/629/friction5mb.png This is my work...

Please? I'm not finding any other relationships.

Now to a little harder problem. A 100kg weight is added on the red spot. Calculate the changes in the normal force reactions at the three wheels due to the weight of the box. http://img110.imageshack.us/img110/7644/car7pu.png In the last one I could use the equations d1/d2 = T2/T1 and...

A car has 4 wheels?:biggrin: Cheers mate, cheers!:-p

This is a lill awkward question but I need to know. A car has the mass 1400kg. What force will be distributed on each tire/tyre? ________________ / \ / \ ____/ \___ | |----d1--|G|-d2-| |...

Hi! I'm woundering what parts/things in physics that's being accepted but hasn't really been prooved yet. Is antineutrinos one of these things? Also if I remember this correctly neutrinos were accepted before they were prooved?

http://www.ugrad.math.ubc.ca/coursedoc/math101/notes/series/taylor.html (I-A)^{-1}=(I+A)\text{, since }A^n=A^2\cdot A^{n-2} = 0\cdot A^{n-2}=0 (I - A)(I + A) = II + IA - AI - AA = I + A - A - 0 = I (I + A)(I - A) = II - IA + AI - AA = I - A + A - 0 = I Now when I've solved this problem...