I am working on exactly same one.
I used I=E/R=(vLB)/R equation to solve C, and had 0.0125A or 1.25*10^-2
but they said it's not quite. :-(
Anyway, there is another question: What is the direction of the induced current?
I know I need to use the right hand rule but can't apply it right.
Is...
Homework Statement
A long, straight wire with linear mass density of 45g/m is suspended by threads, as shown in the figure . There is a uniform magnetic field pointing vertically downward. A 7.0A current in the wire experiences a horizontal magnetic force that deflects it to an equilibrium...
Homework Statement
http://jbworld.jbs.st-louis.mo.us/science/mschober/em3-circuits/E3ws4.pdf
It's the very first one.
Homework Equations
R_eq = delta V / I = [ 1/R_1 + 1/R_n] ^ -1
I = V / R
The Attempt at a Solution
a) So, since the resistors are in parallel, the...
Homework Statement
For the two vectors in the figure , find the magnitude of the vector product lAl x lBl.
http://session.masteringphysics.com/problemAsset/1040325/3/yf_Figure_1_29.jpg
Homework Equations
lAl*lBl=lAl*lBlsin(alpha)
The Attempt at a Solution
2.8cm * 1.9cm * cos(60) =...
Homework Statement
calculate the power dissipated by a resistor R connected to the battery when R = 2.4 ohm.
Homework Equations
I=V/R
The Attempt at a Solution
I found A of battery that given and put R value given to find P, however I cannot get a right answer.
What did I...
well, I have exactly same problem and I solved only one case:
So, we have 10 ohm and 40 watt.
the Power = V^2/ Ohm then we can calculate the volt on 10 ohm.
The power on 20 ohm then, is // resistor with 10 ohm.
Then they should have same potential difference.
So you can...