Recent content by dmsgo89

man, still confused with "out of the page" but.. okay. somewhat got it... Still, nobody for part C ?

I am working on exactly same one. I used I=E/R=(vLB)/R equation to solve C, and had 0.0125A or 1.25*10^-2 but they said it's not quite. :-( Anyway, there is another question: What is the direction of the induced current? I know I need to use the right hand rule but can't apply it right. Is...

F=ILB maybe?

Homework Statement A long, straight wire with linear mass density of 45g/m is suspended by threads, as shown in the figure . There is a uniform magnetic field pointing vertically downward. A 7.0A current in the wire experiences a horizontal magnetic force that deflects it to an equilibrium...

Homework Statement http://jbworld.jbs.st-louis.mo.us/science/mschober/em3-circuits/E3ws4.pdf It's the very first one. Homework Equations R_eq = delta V / I = [ 1/R_1 + 1/R_n] ^ -1 I = V / R The Attempt at a Solution a) So, since the resistors are in parallel, the...

Homework Statement For the two vectors in the figure , find the magnitude of the vector product lAl x lBl. http://session.masteringphysics.com/problemAsset/1040325/3/yf_Figure_1_29.jpg Homework Equations lAl*lBl=lAl*lBlsin(alpha) The Attempt at a Solution 2.8cm * 1.9cm * cos(60) =...

oh and I know P=I*V=V^2/R=RI^2

Homework Statement calculate the power dissipated by a resistor R connected to the battery when R = 2.4 ohm. Homework Equations I=V/R The Attempt at a Solution I found A of battery that given and put R value given to find P, however I cannot get a right answer. What did I...

well, I have exactly same problem and I solved only one case: So, we have 10 ohm and 40 watt. the Power = V^2/ Ohm then we can calculate the volt on 10 ohm. The power on 20 ohm then, is // resistor with 10 ohm. Then they should have same potential difference. So you can...