Finding Power in watt with a real battery

AI Thread Summary
To calculate the power dissipated by a 2.4-ohm resistor connected to a 1.5V battery with an internal resistance of 10 ohms, the correct approach involves using the formula P = I^2 * R. The current (I) can be determined using Ohm's law, I = V / (R_total), where R_total is the sum of the resistor and the battery's internal resistance. The user is struggling to find the correct answer despite knowing the relevant equations. A step-by-step calculation is requested to clarify the process. Understanding the total resistance in the circuit is crucial for accurate power dissipation calculations.
dmsgo89
Messages
9
Reaction score
0

Homework Statement


calculate the power dissipated by a resistor R connected to the battery when R = 2.4 ohm.


Homework Equations


I=V/R


The Attempt at a Solution


I found A of battery that given and put R value given to find P, however I cannot get a right answer.

What did I wrong?

http://session.masteringphysics.com/problemAsset/1021126/12/jfk.Figure.23.P47.new.jpg

The images shows that the battery has 10 ohm and 1.5V.

It is due tonight and I am lost :( please help!
 
Physics news on Phys.org
oh and I know P=I*V=V^2/R=RI^2
 
Please show us exactly what you have calculated and why you calculated it.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Ohm's Law - Finding Source Voltage
Replies
3
Views
1K
Batteries in series, parallel, and internal resistance
Replies
24
Views
5K
Electric Potential across charging battery.
Replies
5
Views
2K
Batteries, Resistance, Power, Potential, and Current
Replies
3
Views
1K
Battery’s terminal potential difference
Replies
2
Views
2K
Calculating Heat Loss in a Series Circuit
Replies
5
Views
4K
How to find the power consumed by the light bulb
Replies
19
Views
3K
Find Internal Resistance From 2 Circuits w/ The Same Battery
Replies
2
Views
2K
Circuit question with two batteries and resistors in pa
Replies
2
Views
2K
How do I calculate the power output of the lightbulb?
Replies
15
Views
11K

Hot Threads

Recent Insights

Back
Top