Recent content by dudy
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Graduate Dynamics in the heizenberg picture
is there a more specific rule? take for example: H = a^\dagger e^{-i\omega t} + a e^{i\omega t} (here a is the annihilation operator). This Hamiltonian is of course time-dependent, but, non-the-less, it is also true that: \frac{dA(t)}{dt} = \frac{i}{\hbar} U^\dagger[H,a]U...- dudy
- Post #3
- Forum: Quantum Physics
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Graduate Dynamics in the heizenberg picture
Hello, The time-derivative of an operator A(t) = U^\dagger a(t)U in the heizenberg picture is given by: \frac{dA(t)}{dt} = \frac{i}{\hbar} [H,A(t)] + U^\dagger(\frac{da(t)}{dt})U Now, I know that under some conditions, we can write: \frac{dA(t)}{dt} = \frac{i}{\hbar} U^\dagger[H,a(t)]U +...- dudy
- Thread
- Dynamics Picture
- Replies: 2
- Forum: Quantum Physics
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Graduate What is the physical meaning of the double rotation symmetry of spin-1/2 states?
Hey, We saw in class that rotating a spin state with an angle of 2pi returns minus the state, and so it has to be rotated 4pi rad in order to return to the original state. However, we also saw that the expected value of the spin DOES return to its original value after a rotation of 2pi rad...- dudy
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- Rotational Symmetry
- Replies: 6
- Forum: Quantum Physics
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Graduate Physical meaning of zero eigenvalue
Thank you very much for the reply! I still don't understand a couple of things.. a. How could m=0 be the ground state, when its energy is 0, and the energy of the other two hamiltonian eigenstates are negative. shouldn't the ground state have the lowest energy? b. what physical mechanism...- dudy
- Post #3
- Forum: Quantum Physics
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Graduate Physical meaning of zero eigenvalue
Hello, Given the hamiltonian : H = -( aS_z^2 + b(S_+^2 +S_-^2) ) with S=1 and a,b>0 are constants. working with the base: { |m=1> , |m=-1> , |m=0> } The matrix form of H is: H = \left( \begin{array}{ccc} -ah^2 & -bh^2 & 0 \\ -bh^2 & -ah^2 & 0 \\ 0 & 0 & 0 \end{array}...- dudy
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- Eigenvalue Physical Zero
- Replies: 4
- Forum: Quantum Physics
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Graduate Hamiltonian and Commuting operators
Wow. Thank you! Very helpful- dudy
- Post #3
- Forum: Quantum Physics
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Graduate Hamiltonian and Commuting operators
Hi, A general question.. In analytical mechanics, we take a given hamiltonian and re-write it in term of generalzed coordinates. In a way- we recode the hamiltonian to concern only the "essence" of the problem. However, it seems to me, that in QM we do the opposite- we look for operators that...- dudy
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- Hamiltonian Operators
- Replies: 2
- Forum: Quantum Physics
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Graduate Induced magnetic field in rings
in this formula the ring is centered at the origin, so its the same- dudy
- Post #5
- Forum: Electromagnetism
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Graduate Induced magnetic field in rings
that was my guess aswell, but B is proportional to I/r, and so the smaller r is- the greater the ring's contribution to the field.- dudy
- Post #3
- Forum: Electromagnetism
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Graduate Induced magnetic field in rings
Hello, Say I have two concentric conducting rings, where r1 >> r2 (why is this important, btw?), and I run a time alternating current I(1) thru the larger one. This will create a magnetic field B (also) thru the smaller ring, which in turn will create itself a magnetic field B2 and so on...- dudy
- Thread
- Field Induced Induced magnetic field Magnetic Magnetic field Rings
- Replies: 4
- Forum: Electromagnetism
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Graduate Lyapunov exponent - order of magnitude
First of all thank you very much for the reply- it is extremely helpful. About the method I'm using- What I did is to take two points from my data that are far apart on the time-line, but have very close values, and watch how the difference (of values) between them grows with time. I repeated... -
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Graduate Lyapunov exponent - order of magnitude
Hello, Analyzing data from a chaotic pendulum, I calculated the Lyapunov exponent to be somewhere around 10^5 . While my gut tells me something is wrong with this number , i failed to find any information regarding the order of magnitude of Lyapunov exponents and their meaning. Can someone... -
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Graduate How come you can express the up and down spins
I don't understand the following regarding spin: 1. How come you can express the up and down spins in any given direction, using the |+>,|-> in the z direction? 2. Why do I need two vectors (|->,|+>) to express a quantity that can only be either (1) or (-1) ?- dudy
- Thread
- Replies: 1
- Forum: Quantum Physics
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Graduate Understanding Expectation Values in Quantum Mechanics
got it, thank you!- dudy
- Post #3
- Forum: Quantum Physics
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Graduate Understanding Expectation Values in Quantum Mechanics
Let A be an observable (opeator), and we're assuming that for a given state psi(x), the value of A is given by A acting on psi(x), namely - A|psi>. Also we assume that - P(x) = |psi(x)|^2 So, I'de expect the Expectation value of A to be defined like so: <A> = Integral[-Inf:+Inf]{ P(x) A...- dudy
- Thread
- Expectation Expectation value Value
- Replies: 2
- Forum: Quantum Physics