Recent content by exuberant.me

finding the max. extension in the spring...! Okkay so i have to calculate the max. extension in a spring attached with two blocks of mass m and M. The box of mass M is pulled with a force F. The system (blocks of masses m1 and m2 and the mass less spring) is placed on a smooth surface...

But where does this outward velocity come from?? Is it imaginary or what is it that keeps the string straight and not slack?

oooo yes i got it that means its just the component of mg that keeps the string tight and at the top most point this component of mg is 0 right...! Thank u!

consider a pendulum. The mass 'm' is hung and now we are interested in finding the velocity so that it completes one circle. Clearly we can do it easily by conserving energy. Now my problem is with the top most point. Clearly the tension is minimum at this point so that string becomes slack...

what about the electric field?

Q) A solid non-conducting sphere of radius R carries non-uniform charge distribution with charge density ρ = ρs(r/R), where ρs is a constant. Show that (a) the total charge on the sphere is Q = ∏ρsR3, and (b) find the electric field inside the sphere. Now first part (a) is fairly easy, assumed...

one more thing at last W = -(U2 - U1) = U1 - U2 So in this question applying W = (U1 - U2) gives me a negative answer but in the book its +ve what of that? :P

God.. i m kind of "fool"... i actually got the answer.. but in the book its given in the form of 'Q' and i got it in terms of 'q' but could not check the difference that time... got it thanks...

A certain charge 'Q' is to be divided into two parts, q and Q-q. What is the relationship of 'Q' to 'q' if the two parts, placed at a given distance 'r' apart, are to have maximum Coulombic repulsion? What is the work done in reducing the distance between them to half its value? It went easy...

yup u r not "pretty right" u r "right" this time and me to.. lol.. :P got it finally... q + q1 = 80 and 2q = 3q1 and simply, Va - Vb = (q - q1)/8 = 16/8 = 2V. Thanks!

Hello all! I actually have a few doubts regarding "gauss law" when applied "for different models of sphere" First, If we place a charge 'Q' inside a spherical shell at the center (somehow) then it should come out to its surface that means in no way can we do it. True or False? Next...

i think i m pretty correct in my soln.. Rather the answer given is wrong...!

i don't knw why i always get those suggestions i probably knw.. :P dear what i want you to do is check what's wrong in my soln... if u cud please point out my mistake, that would help me clear 100 doubts of mine... i obviously have an alternate soln.. the one you posted using it... but they...

Q) In the adjacent circuit, find the potential difference across AB Fine , now i did the charge distribution as follows Now in the first loop (sorry i forgot to mention the points in my image) applying kirchhoffs loop law 10 = q1/8 + q/8 or, q + q1 = 80 Next in the second loop...

i got it cleared at last... actually there was a different problem i faced.. but could not express it here... btw.. i got it cleared by looking carefully.. they have done the right thing.. for first one it lies on the axial line and for second component it lies on equitorial plane.. i could not...