Recent content by Fiorella

Oooh I thought about that...this helps! Thanks a lot!

Solve with convolution integral: Click http://i3.photobucket.com/albums/y62/Phio/eq.jpg" to see the equation. So far what I've got is http://i3.photobucket.com/albums/y62/Phio/attempt.jpg" . I don't know what else to do from there, or if what I'm doing is right... Any help appreciated!

Because T = 85 and K = .058. But something that I noticed that I might have wrong is that the time and temperatures are variables, so at a given time the temperature is going to be something, and at another time something else. Thus, I should keep the equations with the variables without...

I'm trying to solve the problems from this project: http://www.cengage.com/math/book_content/0495108243_zill/projects_archive/de8e/Project7.pdf" I already did problem # 1, and now I'm trying to solve problem # 2, which will help me to solve problem # 3. Solve the differential equation...

Homework Statement Here is a picture of the problem: http://i3.photobucket.com/albums/y62/Phio/34.jpg" Homework Equations y - f(c) = f '(c) (x - c) The Attempt at a Solution 1/(5+x)^1/2 = (5 + x) ^ -1/2 = (1/5)^(1/2) * (1 + x/5)^(-1/2) I have this. But I don't know if I'm on...

oh now I see it...it's obvious. The answer is B. Thanks!

Calculus problem...please help! Homework Statement Here is a picture of the problem: http://i3.photobucket.com/albums/y62/Phio/23.jpg" Homework Equations A = xy = 780 cost = 8x+2y The Attempt at a Solution c = 8x + (1560/x) c'= 8 - ( 1560/(x^2) ) 0 = 8 - ( 1560/(x^2) )...

Thank you so much everybody :)

I posted the image differently :)

Hello, can someone help me solve this integral? I think I need to complete the square...I've tried many other things but I don't know what else to use :confused: and With the last one I did long division and I ended up with: x + x/ (x - 1)...so I can easily solve the first integral...

In a calculus problem I'm doing I have to transform f(x) = 4x^2 - x^3 and y = 18 - 3x in terms of y. I did the second one and it's: x = - (y - 18) / 3 But I can't transform the first one in terms of y :confused:

Ok Dick so I did synthetic division and I got: x^2 - x - 6 (x - 3) (x + 2) (x - 3) (x - 3) x = -2 x=3 -----> so this proves that the line L is tangent to f(x) at x = 3? I know somewhere I have to use derivatives to prove it, but I don't know how :(

Let f be the funtion given by f(x) = 4x^2 - x^3 , let L be the line y = 18 - 3x, where L is tangent to the graph of f. Show that L is the tangent to the graph of y= f(x) at the point x = 3. I'm equaling both graphs like this: 4x^2 - x^3 = 18 - 3x and then I isolate everything...

Thank you SO much you guys :biggrin:! Homeworkboy I have a question...what does "S" and "u" stand for? thank you again lol

Please I need help with these two problems...the answer is in the back of the book but as much as I've tried I can't find the procedure to do them:cry: I really appreciate your help...thank you so much beforehand! 1) The operation manual of a passenger automobile states that the stopping...