Recent content by FiveAlive

Could I use R=5H/20 and plug 3 in as a constant? If you plug in 0, the answer will still be 0 however I am a little unsure what else to try since I can't think of a number that i can multiply times 0 and not get 0, unless I just add 3 on to the end like R= 5h/20 + 3

OK cool I think I get what you're going at. If I put those point on a graph the slope would be a slope of R/H=10/1. I can sub that in for R and put 3 in for r because it's a constant. Simplified it might look a little something like this V= 100H^3(1/3)∏ + 90H^2(1/3)∏ + 9H(1/3)∏ I'm still...

R=5 cm r= 3 cm h= 20 cm

A water glass (10 cm diameter at the top, 6 cm diameter at the bottom, 20 cm in height) is being filled at a rate of 50 cm^3/min. Find the rate of change of the height of the water after 5 seconds. V=(∏* (h/3)) * (R^2 + r^2 +(R*r)) I've been messing around with this for a bit and made a...

Update: Still a little unsure how to resolve the time issue of this problem however I believe I would use the formula V=1/3(3.14)(R^2H-r^2h) to solve for my irregular cone. Am I on the right track?

Update: So I've been looking at my rates of change according to height (at 1 cm, 2 cm, 3 cm ect) and I'd be able to solve it if the cone didn't have a 6 cm diameter. I am still unsure how to tackle this issue.

A water glass (10 cm diameter at the top, 6 cm diameter at the bottom, 20 cm in height) is being filled at a rate of 50 cm^3/min. Find the rate of change of the height of the water after 5 seconds. V=1/3(3.14) r^2h I'm a little unsure how to approach this problem for two reasons. A) The glass...

I think the line must cross the parabola, not just share a point like a tangent line. I only assume this because we did tangent lines a while ago and it seems strange to have an assignment solely about finding them.

Should I assume since my post has many views but no replies that I am on the mark?

I think I know the answer to this problem however I am not 100% sure. I must describe the conditions in which an infinite continuous line (ax+by=c) will only cross a parabola once. I believe the only answer is a straight, vertical line because while the slope of the parabola may approach...

You're brilliant. Thanks again for the help.

Hey thanks so much. Any suggestions for how to rearrange y - b = k(x - a)^2 so it looks more like a quadratic equation?

This is a little more open ended then most HW questions. I'm helping a friend with some HW and we need to transform a parabola. Ultimately we have to find the tangent line, vertex, ect but I'm failing to recall the rules on how to manipulate the parabola to be in the domain of the graph we need...

Is this what you mean? A(0.1) + 12 = B(0.01) +14 A= 20+ B(0.1) Cheers, thanks so much.

I'm working on some voltage/current physics problems and I think I understand the concepts however I believe the algebra is holding me back(not my strong point). Could someone make some suggestions how I could solve for at least one of these variables by using a combination of theses three...