Kirchhoff's rule and multivariable algebra

Click For Summary
SUMMARY

The discussion focuses on solving a set of equations related to Kirchhoff's laws in electrical circuits using multivariable algebra. The equations provided are A + B = H, A(0.1) + 12 = B(0.01) + 14, and B(0.01) + H(1.20) = 12. The user Linus seeks guidance on manipulating these equations to isolate variables, specifically A and B. The solution involves substituting A from the second equation into the third equation to simplify and solve for the unknowns.

PREREQUISITES
  • Understanding of Kirchhoff's voltage and current laws
  • Proficiency in solving linear equations
  • Familiarity with algebraic manipulation techniques
  • Basic knowledge of multivariable algebra concepts
NEXT STEPS
  • Practice solving systems of equations using substitution and elimination methods
  • Explore advanced algebra techniques for multivariable equations
  • Learn about Kirchhoff's laws in greater detail, including practical applications
  • Investigate tools for visualizing electrical circuits and their equations
USEFUL FOR

Students studying electrical engineering, physics enthusiasts, and anyone looking to enhance their algebra skills in the context of circuit analysis.

FiveAlive
Messages
16
Reaction score
0
I'm working on some voltage/current physics problems and I think I understand the concepts however I believe the algebra is holding me back(not my strong point). Could someone make some suggestions how I could solve for at least one of these variables by using a combination of theses three equations?

eq 1) A+B=H

eq 2) A(0.1) + 12 = B(0.01) +14

eq 3) B(0.01) + H(1.20) = 12

I believe that the first step is to expand eq 3 since H=A+B into

B(0.01) + A(1.2) + B(1.2) = 12 but beyond that I am unsure.

thanking you in advance,
Linus
 
Physics news on Phys.org
Solve eq 2) for A. Plug that into your last equation
 
Is this what you mean?

A(0.1) + 12 = B(0.01) +14
A= 20+ B(0.1)


Cheers, thanks so much.
 
FiveAlive said:
Is this what you mean?

A(0.1) + 12 = B(0.01) +14
A= 20+ B(0.1)


Cheers, thanks so much.

Yes.

Now put {20+ B(0.1)} into B(0.01) + A(1.2) + B(1.2) = 12 , in place of A.
 

Similar threads

  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K