Some concepts were unfamiliar, but the book offered a brief introduction to them in any case. I guess I'll have to practice doing these faster then. Thanks for the reply. :)
Am I "ready" for Classical Mechanics?
Hello again, PF. I have a question about the Classical Mechanics course I'm taking this coming fall.
Thanks to having a few cruddy enrollment times in the past year, I've been taking my courses a bit out of order, but without any problems or conflicts...
Alright, so if I have ##vA=\frac{dV}{dt}=A\frac{dy}{dt}##, then plug in y from ##v=\sqrt{2gy}## it looks like ##\frac{dV}{dt}=A\frac{d}{dt}(\frac{v^2}{2g})## which I believe gives me...
$$Q=\frac{dV}{dt}=\frac{Av}{g}$$
Can I say that Volume(final) = Volume(initial) + QΔt and solve for Δt? Or...
Homework Statement
A cylindrical tank of diameter 2R contains water to a depth d. A small hole of diameter 2r is opened in the bottom of the tank. r<<R, so the tank drains slowly. Find an expression for the time it takes to drain the tank completely.Homework Equations...
Yes, using the binomial approximation, I get ##\sqrt{m+Δm}=\sqrt{m} \sqrt{1+\frac{1}{2} \frac{Δm}{m}}##
Hmm I suppose I should find T and ΔT separately next and plug those in...
T+ΔT=2π(1+\frac{Δm}{2m})(\sqrt{m/k})=2π\sqrt{m/k} + 2π\sqrt{Δm/k}
Simplifying I get √(m/k) = 2, so T=4π...
Homework Statement
A mass m oscillating on a spring has a period T. Suppose the mass changes very slightly from m to m+Δm, where Δm << m. Find an expression for ΔT, the small change in the period. Your expression should involve T, m, and Δm, but NOT the spring constant (k).
Homework...
Here's how the book derives ##w=\sqrt{\frac{Mgl}{I}}##, the angular frequency of a physical pendulum:
Something happens to get to that last step that doesn't add up for me... Why is Mgl/I square rooted?
I've been working on problems that deal with pendulums and I've noticed that a few of my answers require me to find the angular velocity, frequency, period of a pendulum. I managed to get the answer right every time, but there's a step that I didn't understand, namely converting angular...
The values 1.8kN and 1.2kN are spot on. I don't know where you got 0.9kN and 2.1kN, though. The tension 1.2kN from the drum should cause a chain of action-reaction pairs along every segment of rope.
The object is in equilibrium, so the net force in the x direction equals zero and the net force in the y direction equals 0. Now solve for that force F in the x and y direction to find its components.
cos 60 should be equal to the vector adjacent to the 60 degree angle divided by the hypotenuse. You're looking for the vector opposite from the angle, so there's a different operation for that.