Recent content by goooogle

The direction for the E-field because of the negative charge would be to the right, so +? In that case, it'd be 16875 - 3600, which is +13275. So I understand that, I think. The units are N/C. The second part was just desperation, trying to find a step I missed. So I take it +13275 N/C is my...

Well, I did ((K)(-3 x10^-9))/(.04^2) + ((K)(4x10^-9)/(.1^2) which gets me -13275. From there, I did -13725 = ((K)(X))/(.1^2) which comes out to -14.75 nano coloumbs. Is that right? Is .1 the right distance for the second part?

"a +4nC charge is 6/0 cm along a horizontal line toward the right of a -3nC charged object. Determine the E field at a point 4.0 cm to the left of the negative charge." From what I understand, it goes Point ___ 4cm ____ (-3nC) _____ 6cm ____ (+4nC) Using that, I got the answer to be -14.75 nC...