Recent content by guillefix
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Graduate Question about non-relativistic limit of QFT
Thanks, and another question Thanks for that! I've got another question though. In the same document, a bit later, he says that one can also derive the Schrödinger Lagrangian by taking the non-relativistic limit of the (complex?) scalar field Lagrangian. And for that he uses the condition...- guillefix
- Post #3
- Forum: Quantum Physics
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Graduate Question about non-relativistic limit of QFT
In pages 41-42 of these notes: http://www.damtp.cam.ac.uk/user/tong/qft/two.pdf , it is said that |\vec{p}|\ll m implies |\ddot{\tilde{\phi}}|\ll m|\dot{\tilde{\phi}}| Why is this so?- guillefix
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- Limit Qft
- Replies: 3
- Forum: Quantum Physics
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Graduate Green's function of the Klein-Gordon operator
That was the key I was missing, probably missed due to writting it so abstractly :P. Thanks!- guillefix
- Post #4
- Forum: Quantum Physics
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Graduate Green's function of the Klein-Gordon operator
Again, from the Peskin and Schroeder's book, I can't quite see how this computation goes: See file attached The thing I don't get is how the term with (\partial^{2}+m^{2})\langle 0| [\phi(x),\phi(y)] | 0 \rangle vanishes, and also why they only get a \langle 0 | [\pi(x),\phi(y)] | 0 \rangle...- guillefix
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- Function Green's function Klein-gordon Operator
- Replies: 4
- Forum: Quantum Physics
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Graduate Why does the Klein-Gordon propagator have a negative i in the exponential?
Hello, I'm looking at the following computation from the Peskin and Schroeder's book: See file attached In the second page, the second term that's being integrated, I don't understand why it has a negative i in the exponential, that'll keep the energy term the same, but will swap the sign...- guillefix
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- Klein-gordon Propagator
- Replies: 2
- Forum: Quantum Physics
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Graduate Commutation relation of the creation/annihilation operators in a field
Thank you for the help, and yeah it was quite lengthy/mistake-prone. I think I found my fundamental mistake. It was in not changing the sign of the i inside the exponential of the Fourier transform of Pi and Phi for the a_dagger. Incidentally, following your definition, I actually arrive to the...- guillefix
- Post #6
- Forum: Quantum Physics
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Graduate Commutation relation of the creation/annihilation operators in a field
Sorry, yeah it's the Klein-Gordon field (in 3+1 dimensions). The expressions I got from the quantum harmonic oscillator, and the fact that the KG field can be considered as one of these per momentum. I haven't verified it in any literature actually, but it made sense, and gave me the right...- guillefix
- Post #3
- Forum: Quantum Physics
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Graduate Total momentum operator for free scalar field
Oh true, that's it! Thank you very much!- guillefix
- Post #3
- Forum: Quantum Physics
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Graduate Total momentum operator for free scalar field
Sorry for reopening a closed thread. But I have exactly the same doubt as this guy: https://www.physicsforums.com/showthread.php?t=346730 And the answer doesn't actually answer his question. I do get delta(p+p'), but they just help me in getting a_{p}a_{-p} and a_{p}^{\dagger}a_{-p}^{\dagger}...- guillefix
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- Field Momentum Operator Scalar Scalar field
- Replies: 2
- Forum: Quantum Physics
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Graduate Commutation relation of the creation/annihilation operators in a field
Hello, I'm having trouble calculating this commutator, at the moment I've got: \left[a_{p},a_{q}^{\dagger}\right]=\left[\frac{i}{\sqrt{2\omega_{p}}}\Pi(p)+\sqrt{\frac{w_p}{2}}\Phi(p),\frac{-i}{\sqrt{2\omega_{p}}}\Pi(p)+\sqrt{\frac{w_p}{2}}\Phi(p)\right]=i\left[\Pi(p),\Phi(q)\right]=i\int...- guillefix
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- Commutation Field Operators Relation
- Replies: 5
- Forum: Quantum Physics
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Graduate Can the Reflectivity of Newton's Rings be Manipulated for Improved Detection?
Yeah, sorry, it's actually quite simple, but should have made it clearer. I decided instead of rotating the bottom surface to displace it a bit, which is maybe more practical?. Anyway, in the picture, the space between the first surface and either of the bottom ones is glass say. The yellow beam... -
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Graduate Can the Reflectivity of Newton's Rings be Manipulated for Improved Detection?
Probably this is an easy question, given that Newton's rings are probably one of the most common and famous light phenomena. In any case, I was wondering that given that say you have the second interface at a position in which the reflectivity on the first is 0, but then you are allowed to... -
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Graduate How Is Energy Flux Calculated in an Electromagnetic Wave?
Just read in here: http://hep.ph.liv.ac.uk/~hutchcroft/Phys258/CN6EMWaves.pdf that I was right yeah. Walter Lewin's lecture was a bit missleading.- guillefix
- Post #2
- Forum: Electromagnetism
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Graduate How Is Energy Flux Calculated in an Electromagnetic Wave?
Hello, The energy density of an electromagnetic wave is ε_{0}E^{2}. To calculate the energy flux, at least in the derivation's I've seen, people just multiply by the speed of the wave, i.e., c. But doesn't this assume that the energy density is constant at all points?; but E changes...- guillefix
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- Em Em wave Energy Flux Wave
- Replies: 2
- Forum: Electromagnetism
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Transient oscillations in transformer?
Yes that's what I meant :P True, I should have posted more detail. The model I've used is quite simple, with just coupled inductors and resistors. The schematic is attached. The equations I used can also be found in hyperphysics here (with another schematic acutally)...- guillefix
- Post #3
- Forum: Electrical Engineering