Recent content by jamesfirst

dunno

1367 * Pi (radius of earth) ^2

a 2d circle

area of the Earth ?

how do you calculate this ? do you use I=Isun (R/d)^2 ?

what do you mean ... ==;; So without using the Earth's radius. I just use σεT^4 and get 394 kelvin ?? can you stop asking rhetorical questions and just tell me... really stressed out here

This is the questionA perfect blackbody is an object that perfectly absorbs and emits radiation across all wavelengths. A very simple 'climate' model is to assume that the Earth is a perfect blackbody and that the temperature is uniform over the surface. Using this model and 6371km for the...

i don't o.0... im confused... can you explain it please.

yeah I get like 394 kelvin

wait so what is the right equation that I should use ?? http://c21.phas.ubc.ca/article/simple-earth-climate-model-additional-concept-explanations is this the right equation ?

T^4 Sigma = stefan-boltzmann constant ??

Assumption: Earth is a perfect blackbody. This means that the emissivity (ε) is 1. Earth’s radius = 6371 km Incident solar radiation = 1367 W/m2 Temperature in space = 0 K I'm given the above data. I tried using the E= σεTe4 but that doesn't include the radius of the Earth :S Im really...

hey it works! thanks. I've been confusing it with the temperature Fahrenheit the whole time ...

I know 1BTU = 1055J 1lb = 1/2.2046 kg 1 F = 255.928 K then 1 BTU/lbF should be 1055/(1.2046)*255.928. But I get 9 plugging this in the value is suppose to be 4186 J/kgK. this is the specific heat of water

Why is the nominal capacity of power plants given in terms of power and not in terms of energy?