Recent content by jeeves_17

  1. J

    Fundamental Theorem of Calculus to find Derivative

    Use the Fundamental Theorem of Calculus to find the derivative of the function g(x) = \sqrt{x}\int sinx Ln(t) \frac{cos(t)}{t} dt g'(x) = lnx cosx / x. By integrating this function, you receive the function g(x). Then by differentiating g(x) you receive g'(x) which is what is...
  2. J

    Rotational Motion of a spun disk

    A 200 g, 20-cm-diameter plastic disk is spun on an axle through its center by an electric motor. What torque must the motor supply to take the disk from 0 to 1800 rpm in 4.0s? (Given: I = ½ MR2) Relevant equations I = 1/2 MR^2 T = Ia The attempt at a...
  3. J

    Speed and Direction after Collision

    i got an angle of 52 degrees and a velocity of 0.94 .. is that right:S
  4. J

    Speed and Direction after Collision

    A 20 g ball of clay traveling east at 2.0 m/s collides with a 30 g ball of clay traveling 300 south of west at 1.0 m/s . What are the speed and direction of the resulting 50g blob of clay? Relevant equations Pi = Pf The attempt at a solution (Px)i = mF(-Vfcostheta) + mP (Vp) =...
  5. J

    Velocity of Car after Unloading Gravel

    ? meaning is it right...sorry for the confusion
  6. J

    What Is the Bird's Speed After Swallowing the Insect?

    P1 = m1*v1 = (0.3)(6.0) = 1.8 P2= m2*v2 = (0.01)(30) =0.3 P1 +P2 = P3 1.8 +0.3 = P3 P3 = 2.1 P3 = m3v3 v3 = p3/m3 = 2.1/0.31 = 6.7741935 = 6.77 m/s?
  7. J

    Velocity of Car after Unloading Gravel

    Pi= mi*vi = (10 000)(2.0) = 20 000 Pi = Pf = 20 000 Pf = mf*vf Vf = Pf/mf = 20 000/14 000 = 1.42857 = 1.43 m/s ?
  8. J

    What Is the Bird's Speed After Swallowing the Insect?

    A 300 g bird flying along at 6.0 m/s sees a 10 g insect heading straight toward it with a speed of 30m/s. The bird opens its mouth wide and enjoys a nice lunch. What is the bird’s speed immediately after swallowing? Relevant equations Jx = m(Vx)f - m(Vx)i Jy = m(Vy)f - m(Vy)i Given...
  9. J

    Velocity of Car after Unloading Gravel

    1. A 10,000 kg railroad car is rolling at 2.00m/s when a 4000kg load of gravel is suddenly dropped in. What is the car’s speed just after the gravel is loaded? Relevant Equations W = 1/2 mv(f)^2 - 1/2 mv(i)^2 3. The Attempt at a Solution [/b] W = 1/2 (14,000kg)v(f)^2 -...
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