Recent content by jensson

that seems like a lot of Newtons! This was an experiment in class with a little motor driven rotator.

can you please show me how you got that? because when I put (0.1488) (331.1^2) (0.05494) that comes out to 896.2 N

is 896.2 N reasonable?

the equation for angular speed we're using is 2pi (n)/elapsed time n is revolutions I think I need to convert this to m/s?

Homework Statement I did an expirement in my physics lab on centripetal force. I'm doing the calculations and right now I am calculating the centripetal force using equation: F= (mass)(angular speed squared)(average radius). My answers are coming out to be huge numbers. ex: (148.8g)(52.70...

Homework Statement A 2.40 kg block is dropped onto a spring and platform of negligible mass. The block is released a distance of 5.00 m above the platform. When the block is momentarily at rest, the spring is compressed by 25.0 cm. Find the speed of the block when the compression of the spring...

Thank you so much!

Nice! Okay, so I use cos in the x direction because the adjacent line to the angle known is in the x direction, and sin in the y direction because the opposite is in the y direction? This changes depending on the triangle and the angle known, yes?

No, I don't know how to resolve vectors.. I'm taking calc I and physics concurrently so I'm a little behind. I also am not sure how to draw a triangle representing the initial velocity (or anything for that matter).

Homework Statement This is a more general question... but here is a specific example in which I don't know why sin is used where it is and why cos is used where it is. I don't need the problem worked out or anything (I have it worked out by my professor), I just need to understand why sin and...

Homework Statement A 7.5 kg box is being lifted by means of a light rope that is threaded through a single, light, frictionless pulley that is attached to the ceiling. a) If the box is being lifted at a constant speed of 2.0 m/s, what is the power delivered by the person pulling on the...

the magnitude for the position vector is like the velocity vector, right? Just instead of using velocity of x and y, I am using their positions. But the equations are the same, yes? Anyway, in that case I got magnitude = square root of 36^2 + 15^2 = 39 m and direction = inverse tan...

anyone?

Okay so the V vector = (10 m/s)i - (3 m/s)j (I had miscalculated there) I don't know why I put 38 - 4 = 32, I have it written down correctly. I guess I didn't check my post for errors. This is my first physics class and when we've dealt with the y direction we've always used gravity, which is...

for the ball thrown downward, I know the x and y components are initial v cos theta and initial v sin theta so if I'm solving for the speed, would I have V(for x) = initial v cos theta and V(for y) = initial v sin theta - gt for distance: x = h + (init v cos theta) (t) y = h...