Recent content by joex444

Hmm... ok, so I think I figured it out. Even though it is uncharged, it has charged quarks. Unlike the electron, neutrons aren't elementary so I can't think of them in that way. This explains why it does precess, as my paper indicates you can actually observe the interfence pattern caused by...

We all know that the magnetic moment is (gq/2m)J, so then why does a neutron precess in a magnetic field if q=0? This should cause the Hamiltonian to be 0.

Thanks, that's really neat. Usually we assume k(x) to be a constant, n, so obviously k'(x) would be 0 and the second term drops, leaving us with the power rule.

I'm a tutor in physics, but was asked this question: What is the derivative of sin(x)^ln(x), with respect to x? I'm not sure how you would go about taking the derivative of a function raised to a function. Is there a general for for d/dx ( f(x)^g(x) )? I understand the answer involves a...

Homework Statement What is the gravitational force caused by a thin uniform rod of length L on a point mass located perpendicular to the rod at it's center? Assume the point mass is a distance R perpendicular to the rod. Homework Equations g = - \frac{GM}{r^2}\hat{r} = - G\rho \int...

Just looking at this quickly, I see that N = mg + Fsin(20) = 14g + 78sin(20)... Then, as you're aware, F_{k}=\mu N and W_{friction} = F_{k} \cdot D

I agree, solve for x1 and x2 in terms of x3, or some equivelant expression. Then knowing that x1, x2 and x3 are integers you can generate all the combinations. Wanted to add to your conclusions, though, pennies can only be 3, 8, 13. I would reccomend you solve for x3 being pennies, then you...

A is given, it is the vector. It's in the first line... Of course, to solve for A in spherical I worked backwards from the answer (I needed an R^5 in the final answer, and the divergence in spherical gives me an integral of a partial of r^2 * A, so obviously r^2 * A needs to have a 5th power...

Homework Statement Find \int_{s} \vec{A} \cdot d\vec{a} given \vec{A} = ( x\hat{i} + y\hat{j} + z\hat{k} ) ( x^2 + y^2 + z^2 ) and the surface S is defined by the sphere R^2 = x^2 + y^2 + z^2 directly and by Gauss's theorem. Homework Equations \int_{s} \vec{A} \cdot d\vec{a} =...

I suggest you graph the function, it is quite helpful. Rewrite your derivative as \frac{1}{6}sin(\frac{x}{3}) just so you understand easier what the trig function is doing when you set it to 0. Secondly, remember that on a closed interval you must consider the end points for maxima or minima...

OK, ok, so after more wasted time and errors made I have arrived at the following two equations, for C and D in terms of F. C = \frac{(k+k')Fe^{\beta}}{2k'e^{\alpha}} and D = \frac{(k'-k)Fe^{\beta}e^{\alpha}}{2k'} Now, I'm thinking that if I just plug it into one of the first two equations...

I have no idea what's going on here, because the way I see it I now have: \frac{n^2}{x^2}+\frac{1}{x_{0}^2}-\frac{2n}{xx_{0}}-\frac{n}{x^2}+U(x)=E So now the only restriction is that U(x) -> 0 as x -> infinity. Well, I'm not sure what I can do, it seems to me to be 2 unknowns and 1...

So here's how I'm doing this derivative, correctly this time. u = A(\frac{x}{x_{0}})^n du = Ac^{-n}nx^{n-1} v = e^{-x/x_{0}} dv = -\frac{e^{-x/x_{0}}}{x_{0}} \frac{\partial\psi(x)}{\partialx} = udv + vdu \frac{\partial\psi(x)}{\partialx} = \psi(x)(\frac{-1}{x_{0}}+\frac{n}{x})...

Now, I get: C = -\frac{k+k'}{k-k'}e^{-2\alpha}D and I can obviously solve that backwards for D. So now I have an equation for C in terms of D. I'm solving for B. I'm having so much trouble with the fact that the powers of e are opposite. I know they don't drop out, because the equation...

I think this may help you http://scienceworld.wolfram.com/physics/Half-InfiniteSquarePotentialWell.html I had a similar problem and it did. Your psi functions don't look right for the two regions x>0. Also, E<Vo implies a bound particle, it will be in the well, but may leak into the...