Recent content by Kandycat

  1. K

    Switching research groups without burning bridges?

    I'm currently a third year undergraduate doing semiconductor research for about one semester and a summer and I absolutely hate it! My professor doesn't have that many grad students and his lab is severely under funded. I don't have my own mentor/grad student and I've been blindly doing a...
  2. K

    Faraday's Law of Induction and Current

    Homework Statement A 22.0-cm-diameter coil consists of 20 turns of circular copper wire of 2.6 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 8.65 x 10-3 T/s. Determine (a) the current in the loop, and (b) the rate at which thermal energy...
  3. K

    Magnetic Force of a copper wire

    So are you saying that 2*F*cos30 = ρ*v*g?
  4. K

    Magnetic Force of a copper wire

    Homework Statement The top wire is 1.00 mm diameter copper wire and is suspended in air due to the two magnetic forces from the bottom two wires. The current flow through the two bottom wires is 95 A in each. Calculate the required current flow in the suspended wire. Homework...
  5. K

    Force on Charge Moving in Magnetic Field

    Is the charge of a proton 1.6E-19 C?
  6. K

    Force on Charge Moving in Magnetic Field

    Homework Statement A proton (mass mp), a deutron (m=2mp, Q = e), and an alpha particle (m = 4mp, Q = 2e) are accelerated by the same potential difference V and then enter a uniform magnetic field B, where they move in circular paths perpendicular to B. Determine the radius of the paths for the...
  7. K

    Comparing Brightness in Series and Parallel Lightbulb Circuits

    When lightbulbs are in a series, they do not receive as much current as the lightbulb in the parallel series. In other words, the brightnest depends on which lightbulb will receive the current.
  8. K

    Solving Electric Current Homework

    Homework Statement A battery with emf, E, and internal resistance, r, is connected to a variable resistance, R, at points X and Y, as shown above on the left. Varying R changes, both the current I and the terminal voltage Vxy. The quantities I and Vxy are measured for several values of R...
  9. K

    Kirchhoff's Rules and terminal voltage

    Okay, so I figure out the currents. I'm still pretty confused with finding terminal voltage. Are you saying that Terminal Voltage = I3r?
  10. K

    Kirchhoff's Rules and terminal voltage

    Okay, can you tell me if my loops are right? Top: V1 + V2 = I1r + I1R1 + I2r + I2R2 + I1R3 Bottom: V3 + I2R2 + I2r = I1r + I3r + I3R5 + V2 + I3R4 Big: V1 + V3 = I1r + I1R1 + I3R4 + I3r + I3R5 + I1R4
  11. K

    Kirchhoff's Rules and terminal voltage

    Homework Statement (a) Determine the currents I1, I2, I3 in the figure. Assume the internal resistance of each batter is r = 1.0 olms (b) What is the terminal voltage of the 6.0 V battery? I hope you can read my handwriting. Homework Equations V = IR The Attempt at a...
  12. K

    Solve Pendulum Problem: Tension 150 N, Mass .65 kg, 28m Apart

    Oh... so is it v = \sqrt{F(t)/(m/L)}? v = \sqrt{150 N/(.65 kg/ 28 m)} = 80.35 m/s T = L/v = 28 m/80.35 m/s = .35 s Thanks! Sorry about that.
  13. K

    Solve Pendulum Problem: Tension 150 N, Mass .65 kg, 28m Apart

    Homework Statement A cord of mass .65 kg is stretched between two supports 28 m apart. If the tension in the cord is 150 N, how long will it take a pulse to travel from one support to the other? Homework Equations umm... the only equation to find helpful was... T = 2pi\sqrt{m/(mg/L)}...
  14. K

    Torque Equilibrium: Find Mass & Center of Gravity

    Just to make sure I'm right... I figured this: At the 50 cm fulcrum: 0 = (.300 kg)(25 cm) - (.150 kg)(40 cm) - x(50 cm-L) 0 = 1.5 - x(50-L) 1.5 = x(50-L) At the 43 cm fulcrum: 0 = (.150 kg)(32 cm) + x(L - 43 cm) - (.300 kg)(33 cm) 0 = -5.1 + x(L - 43 cm) 5.1 = x(L - 43 cm) So using...
  15. K

    Torque Equilibrium: Find Mass & Center of Gravity

    So this is what I figure out... somewhat: T1 = T2 + T3 When the fulcrum is at 50 cm: (.300 kg)(25 cm) = XL + (.150 kg)(40 cm) When the fulcrum is at 43 cm: (.150 kg)(32 cm) + XL = (.300 kg)(33 cm) X= the mass of the meter stick L= the position where the center of gravity from the...
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