Force on Charge Moving in Magnetic Field

AI Thread Summary
The discussion focuses on calculating the radius of circular paths for a proton, deuteron, and alpha particle moving in a magnetic field after being accelerated by the same potential difference. The relevant equation for the radius is r = mv/qB, where m is mass, v is velocity, q is charge, and B is the magnetic field strength. It is noted that the energy acquired by the particles from the potential difference can be equated to their kinetic energy, leading to the need to find their velocities. The charge of a proton is confirmed as 1.6E-19 C, but this specific value is deemed unnecessary for comparing the radii. The solution approach involves calculating the velocities for each particle and substituting them into the radius formula to derive the relationships.
Kandycat
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Homework Statement


A proton (mass mp), a deutron (m=2mp, Q = e), and an alpha particle (m = 4mp, Q = 2e) are accelerated by the same potential difference V and then enter a uniform magnetic field B, where they move in circular paths perpendicular to B. Determine the radius of the paths for the deuteron and alpha particle in terms of that for the proton.

Homework Equations


r = mv/qB

r= radius
m=mass
v=velocity
q=charge
B=magnetic field

The Attempt at a Solution


I thought V = delta PE = delta KE = delta (1/2)mv2

And then I got confused.
 
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When the charged particles are accelerated in a potential difference V,energy acquired by them is given by qV, where q is the charge on it. And it can be equated to its KE. First of all find the velocity of each particle and substitute in the formula for radius and compare them.
 
Is the charge of a proton 1.6E-19 C?
 
Yes. But to solve this problem this value in not needed, because you are comparing radii.
 
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