Recent content by Ling_Ling

Oh. I see now. So it would be: 6.2 mL - .2657 mL = 5.343 mL I forgot that if the glass is contracting, there would be less room since it's the container of the liquid.

Oh. My apologies, a misinterpretation of variables, thanks to past physics units. So then: ½mv² = 3/2 kT ½m(1.014)² = 3/2 (1.38E-23)T 2.484E22 m = T Although, I'm not really sure how I could find m (assuming the above steps are correct?) Unless I should just use the equation...

Okay, thank you. I just needed to check that I had the right work and thinking.

Homework Statement The rms speed of molecules in a gas at 20.0°C is to be increased by 1.4 percent. To what temperature must it be raised? k = 1.38E-23 (Boltzmann's Constant) Ratio in speed: 1.014 : 1 Ratio in Volume: 1.014² = 1.0282 : 1 T1 = 20°C = 293°K The Volume of 1 mol of an ideal...

Homework Statement If 2.00 m³ of a gas initially at STP is placed under a pressure of 5.00 atm, the temperature of the gas rises to 39.0°C. What is the volume? STP means it's at 0°C and 1 atm of Pressure, correct? V1 = 2.00 m³ V2 = ? T1 = 0°C = 273°K (My main confusion was units: °C...

Homework Statement A brass plug is to be placed in a ring made of iron. At room temperature (20°C), the diameter of the plug is 8.749 cm and that of the inside of the ring is 8.739 cm. They must both be brought to what common temperature in order to fit? It's a linear expansion problem...

An ordinary glass is filled to the brim with 360.0 mL of water at 100°C. If the temperature decreased to 18°C, how much water could be added to the glass? Volume Expansion Coefficient for Water ß (C°)^-1 (I believe then, that I use Celsius and not Kelvin?) ß(water) = 210E-6 ß(glass) = 9E-6...