Recent content by Northbysouth

I'm working on a senior design project. Currently I'm having some issues with sizing a motor for a large robot; everywhere I look I get different advice. I have a motor that I think will work but would appreciate some input. The specs are for our robot are as follows: mass = 350 lb = 158.8 kg...

I've added the [Code] tags but I'm not sure what you mean by Matlab routines.

Homework Statement Numerically integrate and plot the response of an underdamped system determined by m= 100 kg, k= 20,000 N/m, and c = 200 kg/s, subject to the initial conditions of x0 = 0.01 m and v0 = 0.1 m/s, and the applied force F(t)=150cos(5t). Then plot the exact response. Homework...

Homework Statement For he following Fourier series, which of the answers correctly describes the following function y(t) = 2 - \stackrel{1}{π}∑1inf1/nsin(n*πt/2) a) odd function, period = 2 s b) Even function, period = 2s c) Odd function, period = 4s d) Even functio, period = 4s...

Thank you so much. I'll admit I still don't fully understand. My final code was w_n=2; %rad/s x_0=1; %mm v_0=0; %mm/s z=0.8; %this value varies, thereby changing the response of the plot t=[0:0.1:20]; w_d=w_n*sqrt(1-z^2); x=x_0*exp(-z*w_n*t).*sin(w_d*t); plot(t,x) Which by changing z for...

Homework Statement Plot x(t) for a damped system of natural frequency w_n= 2 rad/s and initial conditions x_0= 1 mm and v_0 = o mm/s, for the following values of the damping ratio: z= 0.01, 0.2, 0.6, 0.1, 0.4 and 0.8 Homework Equations The Attempt at a Solution I began by defining...

I've got a TI-89 Titanium I've taking a class in Mechanical Design and my professor informs me that we need to be able to solve the equation (equation 3-15) shown in the attachment. I've been trying to find a way to program it into my calculator, but haven't had any real success. The...

Because after each term is multiplied by s2(s2+w2) we're left with 1 = A(s2+w2) + Bs(s2+w2) + cs2 + Dss2 Which simplifies to 1 = As2 + Aw2 + Bs3 + Bsw2 + cs2 + Ds3 evaluating at s=0 We have 1 = Aw2 A = 1/w2

Yes, I did that. You were right. The left side of the equation became 1 whereas everything else but A turned to 0 1 = A(s2+w2) A = 1/w2 Did we choose w=0 because it as convenient for us, as it left us with only A? What would be the best method to solve for B? I had considered...

So, I multiplied both sides by s2(s2+w2) which left me with: 1 = As2+Aw2 Solving for A I get A = 1/(s2+w2) Why was s=0? Could I do something similar to find B, like use s(s2+w2) on both sides?

So, as I understand it. I have s=0, 0, -w, w. s2*1/(s2(s2+w2)) evaluated at s=0 So, then I'd have A = 1/w2

Okay, I've solved it for X(s) and used the initial conditions x(0)=0 and x'(0)=0 This gives me: x(s) = 1/(s2(s2+wn2)) Which I can break down into: s/(s2+ wn2) * 1/s3 From the tables this, I think, gives me: cos(wnt) * t2/2 How does this look?

So, now I would solve for X(s), but what would I do after this point? Would I need partial fractions?

I was thinking it looked a bit odd. So Should it instead be: [sL{x''} - x'(0)] + wn2[X(s) - x(0)] = 1/s2 This simplifies to: s2X(s) - sx(0) - x'(0) + wn2X(s) - wn2x(0) = 1/s2

Homework Statement Obtain the solution of the differential equation x'' + w2nx = t My use of L refers to the Laplace Homework Equations The Attempt at a Solution L{x'' + w2nx = t} I decided to do the Laplace of each part individually starting with x'' L{x''} =...