I'm working on a senior design project. Currently I'm having some issues with sizing a motor for a large robot; everywhere I look I get different advice. I have a motor that I think will work but would appreciate some input.
The specs are for our robot are as follows:
mass = 350 lb = 158.8 kg...
Homework Statement
Numerically integrate and plot the response of an underdamped system determined by m= 100 kg,
k= 20,000 N/m, and c = 200 kg/s, subject to the initial conditions of x0 = 0.01 m and v0 = 0.1 m/s, and the applied force F(t)=150cos(5t). Then plot the exact response.
Homework...
Homework Statement
For he following Fourier series, which of the answers correctly describes the following function
y(t) = 2 - \stackrel{1}{π}∑1inf1/nsin(n*πt/2)
a) odd function, period = 2 s
b) Even function, period = 2s
c) Odd function, period = 4s
d) Even functio, period = 4s...
Homework Statement
Create a VI that will: simulate two sine waves of different frequencies (run it
for 20 and 12 0 Hz). Add the sine waves and plot the sum. Then use a filter to
remove signals above 50 Hz, and plot
the filtered resHomework Equations
The Attempt at a Solution
I have attached an...
Thank you so much. I'll admit I still don't fully understand. My final code was
w_n=2; %rad/s
x_0=1; %mm
v_0=0; %mm/s
z=0.8; %this value varies, thereby changing the response of the plot
t=[0:0.1:20];
w_d=w_n*sqrt(1-z^2);
x=x_0*exp(-z*w_n*t).*sin(w_d*t);
plot(t,x)
Which by changing z for...
Homework Statement
Plot x(t) for a damped system of natural frequency w_n= 2 rad/s and initial conditions x_0= 1 mm and v_0 = o mm/s, for the following values of the damping ratio: z= 0.01, 0.2, 0.6, 0.1, 0.4 and 0.8
Homework Equations
The Attempt at a Solution
I began by defining...
I've got a TI-89 Titanium
I've taking a class in Mechanical Design and my professor informs me that we need to be able to solve the equation (equation 3-15) shown in the attachment. I've been trying to find a way to program it into my calculator, but haven't had any real success.
The...
Because after each term is multiplied by s2(s2+w2)
we're left with
1 = A(s2+w2) + Bs(s2+w2) + cs2 + Dss2
Which simplifies to
1 = As2 + Aw2 + Bs3 + Bsw2 + cs2 + Ds3
evaluating at s=0
We have
1 = Aw2
A = 1/w2
Yes, I did that. You were right. The left side of the equation became 1 whereas everything else but A turned to 0
1 = A(s2+w2)
A = 1/w2
Did we choose w=0 because it as convenient for us, as it left us with only A?
What would be the best method to solve for B?
I had considered...
So, I multiplied both sides by s2(s2+w2) which left me with:
1 = As2+Aw2
Solving for A I get
A = 1/(s2+w2)
Why was s=0?
Could I do something similar to find B, like use s(s2+w2) on both sides?
Okay, I've solved it for X(s) and used the initial conditions x(0)=0 and x'(0)=0
This gives me:
x(s) = 1/(s2(s2+wn2))
Which I can break down into:
s/(s2+ wn2) * 1/s3
From the tables this, I think, gives me:
cos(wnt) * t2/2
How does this look?
I was thinking it looked a bit odd.
So Should it instead be:
[sL{x''} - x'(0)] + wn2[X(s) - x(0)] = 1/s2
This simplifies to:
s2X(s) - sx(0) - x'(0) + wn2X(s) - wn2x(0) = 1/s2