Recent content by NP04

ΔL= αLoΔT ΔL = (23*10^-6)(0.2480 m)(28.30°C) ΔL = 1.61 * 10^-4 Period is 1s, so each second the pendulum moves 1.61 * 10^-4 m 1.61 * 10^-4 m/s *(60s/1min)*(60min/1hr)*(24hr/1day) = 13.95 m/day T = s (1:1 ratio) 13.95 seconds. But the answer is actually 69.3 s. Is the equation T = 2π√L/g...

M F Ice Point 77°M 32°F Steam Point 437°M 212°F 437°M - 77°M = 360°M 212°F - 32°F = 180°F ∴ M = 2F M = 2(68°) M = 136° But this is incorrect. The answer is actually 149°M. Please help.

Deriving the surface area is only the first step. Here is the full problem (related rates): Water flows at 8 cubic feet per minute into a cylinder with radius 4 feet. How fast is the water level rising when the water is 2 feet high? Answer should be expressed in terms of feet per minute.

I think I understand what you mean. The x should be a v, right?

If you are referencing the "a" term, that is πr^2.

Using product rule, we have: [d/dx] (πr^2)(h) = (πr^2)(1 ) + (2πr)(h) Why is the two there? V = 2 πrh+2πr^2 The derivative of h is 1, not 2. Please help!

Ok, so I'm asking what they are. We did a lab on this in class.

There is slit separation, slit width, distance between center maximum. I just don't know which variable corresponds to each.

I know I have to use λ=xd/L. But I don't know what any of those variables (except lambda) mean. If you assume that 0.59 is x times d, you can get an answer that is close. 0.59/100 = 5.9*10^-3. Can someone explain the solution and meanings of variables using a diagram? (The answer to the...

Magnification |M|<1 = smaller |M|>1 = larger This is my reasoning because the magnification is -d0/di so it is the ratio that matters. Because wouldn't the sign just affect the type of image?? If you consider the sign in image size, you are saying that only one type of image (real/virtual)...

I substituted and got ((xn/2nn!) + 1)/(xn/2nn!). I then multiplied by 2nn! to each side and got (xn + 2nn!)/(xn). Now I am confused as to what my next step should be.

I think I can eliminate A because the equations depict a linear relationship. Since the gauge pressure is in a linear relationship with the absolute pressure, I would say exactly 2, but the answer is d.

Problem Statement: Determine whether f is continuous at c. (see image for piecewise function f) EDIT: Sorry if it is a little blurry that is x^3 in the numerator of the rational function and x^2 in the denominator Relevant Equations: Basic understanding of limits My work: Since the...

Well...I am not sure what formula you are referencing, but would it be just adding 1/2λ to the fundamental 1/2λ(which is given)? Then L = λ, so v = λf, which does not make sense. The harmonic asked for is the 2nd one. But since the speed in the tube is already 2Lf I am confused. In part D...

I do not understand parts c and d. For part C I have no idea where to start. And for part d, I got 1/4λ = L (open-close tube fundamental harmonics) so λ = 4L. But the answer key says it is 1/2 L. Help!