Recent content by Oribe Yasuna

deltaV = Ed But I'm missing both E and d? d is the separation between the plates but the variable d in the image seems to be a length.

1/2 mv^2 = q deltaV This kinetic energy equation? mv^2 = 2q deltaV v^2 = 2q deltaV / m v = sqr rt (2q delta V / m)

Homework Statement In the simple mass spectrometer shown in the figure below, positive ions are generated in the ion source. They are released, traveling at very low speed, into the region between two accelerating plates between which there is a potential difference ΔV. In the shaded region...

I plugged in the numbers and I got -4.8e+2 (-4.8 * 10^2). The answer was correct. Thanks for the help, I probably would have over-complicated things without it.

Alright. Since this is on the y-coordinate I'll exclude the x & z coordinates of the vectors: delta V = integral of P1 -> P2 (1 / 4 pi E0 * 2 q s / y^3) dy delta V = 1 / 4 pi E0 * 2 q s * integral of P1 -> P2 (1 / y^3) dy In this form, the problem seems to become easier than I expected it to...

I wanted to avoid doing an integral and instead get an estimate. I suppose that's an unreasonable expectation, though. Then, this is the integral I set up: delta V = integral of 0.02 -> 0.06 [(1 / 4*pi*E0) * (2*6e-9*0.004 / y^3) * (<dx, dy, dz>)] I know: delta L = <dx, dy, dz> delta L = 0.04 m...

Homework Statement A dipole is centered at the origin, with its axis along the y axis, so that at locations on the y axis, the electric field due to the dipole is given by E vector = 0, 1/4πε0 * 2qs/y^3, 0 V/m The charges making up the dipole are q1 = +6 nC and q2 = -6 nC and the dipole...

No, it's the acceleration of the system of rods and disk. Would the string's movement be measured in torques?

d = 1/2 at^2 0.023 = 1/2 (13.2)t^2 0.059032605 = t omegaf = omegai + RFt / I omegaf = (0.05)(33)(0.059032605) / 0.009305 omegaf = 10.46789879 rad./s Okay, does that look correct?

Alright. So the first question is asking for the velocity of the system. The rotation of the disk is related to angular velocity, so that's not it. So the center of the system (center of the disk) has moved a distance of 0.034 m, which is d in the equation. d = v1 + 1/2 at^2 d = 1/2 at^2 0.034...

Well, I tried calculating them separately using the same formula and got different times. But there can only be one time, so I thought it was wrong.

I don't remember a formula like that at all. All I could find was: d = v1 + 1/2 at^2 d = 1/2 at^2 0.034 + 0.023 = 1/2 13.2 t^2 0.057 = 6.6t^2 0.008636364 = t^2 0.092932038 = t t = (vf - vi) / a 0.092932038 = vf / 13.2 1.2267... = vf That doesn't look right though.

F = ma a = m/F a = 33 N / (1.3 kg + 0.3 kg + 0.3 kg + 0.3 kg + 0.3 kg) a = 13.2 m/s^2 Maybe... 0.034 * 13.2 = 0.4488 m^2 / s^2 0.023 * 13.2 = 0.3036 m^2 / s^2 0.4488 + 0.3036 = 0.7524 m^2 / s^2 sqrt 0.7524 = 0.8674... m/s I'm just guessing through units, but is this it?

I don't understand how to get velocity from that. Is there a formula?

That the disk is rotating and the system is moving at different rates?